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Sloan [31]
3 years ago
8

What mass of oxygen would form from 2.30 moles of water?

Chemistry
1 answer:
Serggg [28]3 years ago
8 0

Answer : The mass of oxygen will be, 36.8 grams

Solution : Given,

Moles of water = 2.30 moles

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of oxygen.

The balanced chemical reaction will be,

2H_2O\rightarrow 2H_2+O_2

From the balanced reaction we conclude that

2 moles of water decomposes to give 1 mole of O_2

2.30 moles of water decomposes to give \frac{2.3}{2}=1.15 moles of O_2

Now we have to calculate the mass of oxygen.

\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2

\text{Mass of }O_2=(1.15moles)\times (32g/mole)=36.8g

Therefore, the mass of oxygen will be, 36.8 grams

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Answer:

a) The pH of the solution is 12.13.

b) The pH of the solution is 12.17.

Explanation:

Ionic product of water =K_w=1.01\times 10^-{14}

K_w=[H^+][OH^-]

1.01\times 10^-{14}=[H^+][OH^-]

Taking negative logarithm on both sides:

-\log[1.01\times 10^-{14}]=(-\log [H^+])+(-\log [OH^-])

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So, [OH^-]=1\times [NaOH]=1\times 1.39\times 10^{-2} M=1.39\times 10^{-2} M

pOH=-\log[1.39\times 10^{-2} M]=1.86

13.99=pH+pOH

13.99=pH+1.86

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pOH=-\log[0.0153 M]=1.82

13.99=pH+pOH

13.99=pH+1.82

pH=13.99-1.82=12.17

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