Ask question

Ask question

All categories

3 years ago

13

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater

than atmospheric pressure? The density of glycerine is 1.26 × 10 3 kg/m 3 .

1 answer:

abruzzese [7]3 years ago

6 0

Answer: 0.176 m

Explanation:

Given

Pressure of glycerine, p = 2170 Pa

Density of glycerine, ρ = 1.26*10^3 kg/m³

Depth, h = ?

To solve, we use the formula of pressure

P = ρgh

Where

ρ = density of glycerine

P = pressure of glycerine

g = acceleration due to gravity

h = depth of glycerine

2170 = 1.26*10^3 * 9.8 * h

2170 = 12348 * h

h = 2170 / 12348

h = 0.176 m

Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m

You might be interested in

A plane electromagnetic wave, with wavelength 5 m, travels in vacuum in the positive x direction with its electric vector E, of

Dafna1 [17]

Answer:

Explanation:

E₀ = 229.1 V/m

E = E₀ / √2 = 229.1 / 1.414 = 162 V/m

B = E / c ( c is velocity of em waves )

= 162 / (3 x 10⁸) = 54 x 10⁻⁸ T

rate of energy flow = ( E x B ) / μ₀

= 162 x 54 x 10⁻⁸ / 4π x 10⁻⁷

= 69.65 W per m².

5 0

3 years ago

A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha

mylen [45]

Answer:

Rotational kinetic energy = 0.099 J

Translational kinetic energy = 200 J

The moment of inertia of a solid sphere is $I = \frac{2}{5}mr^2$ .

Explanation:

Rotational kinetic energy is given by

$\text{RKE} = \frac{1}{2}I\omega^2$

where <em>I</em> is the moment of inertia and <em>ω</em> is the angular speed.

For a solid sphere,

$I = \frac{2}{5}mr^2$

where <em>m</em> is its mass and <em>r</em> is its radius.

From the question,

<em>ω</em> = 49 rad/s

<em>m</em> = 0.15 kg

<em>r</em> = 3.7 cm = 0.037 m

$\text{RKE} = \frac{1}{2}\times \frac{2}{5} mr^2\omega^2 = \frac{1}{5} mr^2\omega^2$

$\text{RKE} = \frac{1}{5} (0.15\ \text{kg})(0.037\ \text{m})^2(49\ \text{rad/s})^2 = 0.099\text{ J}$

Translational kinetic energy is given by

$\text{TKE} = \frac{1}{2} mv^2$

where <em>v</em> is the linear speed.

$\text{TKE} = \frac{1}{2} (0.15\ \text{kg})(52\ \text{m/s})^2 = 200\text{ J}$

5 0

3 years ago

Read 2 more answers

You are creating a carbon cycle poster. What could you include in the poster to demonstrate the cycling

nalin [4]

Answer:

the answer should be d.

3 0

4 years ago

A typical car has 16 L of liquid coolant circulating at a temperature of 95 ∘C through the engine's cooling system. Assume that,

amm1812

Answer:

$\Delta V=0.0592\ L$

Explanation:

Given:

Initial temperature of the coolant, $T_f=95^{\circ}C$

final temperature of the coolant, $T_f=105^{\circ}C$

total volume of the coolant, $V_c=16\ L$

coefficient of volume expansion for coolant, $\beta_c=410\times 10^{-6}\ ^{\circ}C^{-1}$

volume of Al radiator, $V_a=2\ L$

volume of steel radiator, $V_s=14\ L$

<u><em>We have:</em></u>

coefficient of volume expansion for Aluminium, $\beta_a=75\times 10^{-6}\ ^{\circ}C^{-1}$

coefficient of volume expansion for steel, $\beta_a=35\times 10^{-6}\ ^{\circ}C^{-1}$

<u>Now, change in volume of the coolant after temperature rises:</u>

$\Delta V_c=V_c.\beta_c.\Delta T$

$\Delta V_c=16\times 410\times 10^{-6}\times (105-95)$

$\Delta V_c=0.0656\ L$

<u>Now, volumetric expansion in Aluminium radiant:</u>

$\Delta V_a=V_a.\beta_a.\Delta T$

$\Delta V_a=2\times 75\times 10^{-6}\times (105-95)$

$\Delta V_a=0.0015\ L$

<u>Now, volumetric expansion in steel radiant:</u>

$\Delta V_s=V_s.\beta_s.\Delta T$

$\Delta V_s=14\times 35\times 10^{-6}\times (105-95)$

$\Delta V_s=0.0049\ L$

∴Total extra accommodation volume created after the expansion:

$V_X=\Delta V_s+\Delta V_a$

$V_X=0.0049+0.0015$

$V_X=0.0064\ L$

Hence, the volume that will overflow into the small reservoir will be the volume of coolant that will be extra after the expanded accommodation in the radiator.

$\Delta V=\Delta V_c-\Delta V_X$

$\Delta V=0.0656-0.0064$

$\Delta V=0.0592\ L$

3 0

3 years ago

What is a solenoid?

babymother [125]

Answer:

A. A current-carrying sure with many coils

Explanation:

A solenoid is a coil that when current passes through a magnatic field if created.

6 0

3 years ago