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MrRa [10]
3 years ago
13

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater

than atmospheric pressure? The density of glycerine is 1.26 × 10 3 kg/m 3 .
Physics
1 answer:
abruzzese [7]3 years ago
6 0

Answer: 0.176 m

Explanation:

Given

Pressure of glycerine, p = 2170 Pa

Density of glycerine, ρ = 1.26*10^3 kg/m³

Depth, h = ?

To solve, we use the formula of pressure

P = ρgh

Where

ρ = density of glycerine

P = pressure of glycerine

g = acceleration due to gravity

h = depth of glycerine

2170 = 1.26*10^3 * 9.8 * h

2170 = 12348 * h

h = 2170 / 12348

h = 0.176 m

Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m

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Answer:

The amount of work the factory worker must to stop the rolling ramp is 294 joules

Explanation:

The object rolling down the frictionless ramp has the following parameters;

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The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp

Where;

The potential energy P.E. = m × g × h

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Therefore, we have;

P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules

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Hope this helps :)
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