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MrRa [10]
3 years ago
13

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater

than atmospheric pressure? The density of glycerine is 1.26 × 10 3 kg/m 3 .
Physics
1 answer:
abruzzese [7]3 years ago
6 0

Answer: 0.176 m

Explanation:

Given

Pressure of glycerine, p = 2170 Pa

Density of glycerine, ρ = 1.26*10^3 kg/m³

Depth, h = ?

To solve, we use the formula of pressure

P = ρgh

Where

ρ = density of glycerine

P = pressure of glycerine

g = acceleration due to gravity

h = depth of glycerine

2170 = 1.26*10^3 * 9.8 * h

2170 = 12348 * h

h = 2170 / 12348

h = 0.176 m

Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m

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Each of the four expansion models (recollapsing, critical, coasting, and accelerating) predict different ages for the universe,
cupoosta [38]

Answer:

This is because the age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

Explanation:

The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.

4 0
3 years ago
A 70.9-kg boy and a 43.2-kg girl, both wearing skates face each other at rest on a skating rink. The boy pushes the girl, sendin
Lelechka [254]

Answer:

Explanation:

Given

mass of boy m_b=70.9\ kg

mass of girl m_g=43.2\ kg

speed of girl after push v_g=4.64\ m/s

Suppose speed of boy after push is v_b

initially momentum of system is zero so final momentum is also zero because momentum is conserved

P_i=P=f

0=m_b\cdot v_b+m_g\cdot v_g

v_b=-\frac{m_g}{m_b}\times v_g

v_b=-\frac{43.2}{70.9}\times 4.64  

v_b=-2.82\ m/s

i.e. velocity of boy is 2.82 m/s towards west                

8 0
3 years ago
Light striking a mirror at a 50° angle will be reflected at an angle _____.
Stells [14]
Equal to 50


law of reflection: angle of incidence equals angle of reflection
5 0
3 years ago
Read 2 more answers
What is E of a hydrogen atom in the 3p state?
notsponge [240]

Answer:

E=-1.51 eV.

L=\hbar\sqrt{2}

Explanation:

The nth level energy of a hydrogen atom is defined by the formula,

E_{n}=-\frac{13.6}{n^{2} }

Given in the question, the hydrogen atom is in the 3p state.

Then energy of n=3 state is,

E_{n}=-\frac{13.6}{(3)^{2} }\\E_{n}=-1.51eV

Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.

Now, the value of L can be calculated as,

L=\hbar\sqrt{l(l+1)}

For 3p state, l=1

L=\hbar\sqrt{1(1+1)}\\L=\hbar\sqrt{2}

Therefore, the value of L of a hydrogen atom in 3p state is L=\hbar\sqrt{2}.

4 0
3 years ago
10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
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