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MrRa [10]
3 years ago
13

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater

than atmospheric pressure? The density of glycerine is 1.26 × 10 3 kg/m 3 .
Physics
1 answer:
abruzzese [7]3 years ago
6 0

Answer: 0.176 m

Explanation:

Given

Pressure of glycerine, p = 2170 Pa

Density of glycerine, ρ = 1.26*10^3 kg/m³

Depth, h = ?

To solve, we use the formula of pressure

P = ρgh

Where

ρ = density of glycerine

P = pressure of glycerine

g = acceleration due to gravity

h = depth of glycerine

2170 = 1.26*10^3 * 9.8 * h

2170 = 12348 * h

h = 2170 / 12348

h = 0.176 m

Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m

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yanalaym [24]

Answer: A. The total displacement divided by the time and  C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity V will be expressed by the following equation:

V=\frac{d}{t}

Where:

d is the ant's total displacement

t is the time it took to the ant to travel to the kitchen

Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

3 0
3 years ago
Leandra is baking cookies , and they are ready to come out of the oven . Before she takes them out of the oven , she puts her mi
ch4aika [34]

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Explanation:

8 0
3 years ago
PHYSICSSS PLEASE HELP
Aleonysh [2.5K]

Answer:

1. 10.5 Kg

2. s/g

Explanation:

1. Determination of the mass of gasoline

Density of gasoline = 0.7 Kg/L

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The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:

Density = mass / volume

With the above formula, we can obtain the mass of the gasoline as follow:

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

Density = mass / volume

0.7 = Mass of gasoline / 15

Cross multiply

Mass of gasoline = 0.7 × 15

Mass of gasoline = 10.5 Kg

2. Density has various units some are listed below:

I. Kilogram per litre (Kg/L)

II. Kilogram per cubic metre (Kg/m³)

III. Milligram per millilitre (mg/mL)

IV. Gram per millilitre (g/mL)

V. Gram per cubic centimetre (g/cm³)

Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.

3 0
3 years ago
Which of the following causes a current in an electrical circuit?
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C. because you need voltage in a circuit to cause current.
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