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BabaBlast [244]
3 years ago
15

A bicyclist travels at 15 miles per hour south. After 10 minutes, the cyclist is traveling at 20 miles per hour south. Which is

this an example of? A.acceleration B.speed C.velocity
Physics
2 answers:
denpristay [2]3 years ago
7 0
<span>By adding "south", the speed had both magnitude AND direction, becoming a vector, not a scalar which generic "speed" is. So the second option can be eliminated. Let's analyze the other part(s). A velocity is a distance/time. Do we have that? Yes! -> miles/hour. So, velocity is an option that theoretically fits this question. Buttt... It gives us a time, and acceleration is a change in a velocity (speed, with a direction)/time. So because it says "after 10 minutes", we consider the big picture to be talking about the change in velocity during that time span, which is simplified as "the acceleration" over that time. :)</span>
Basile [38]3 years ago
4 0
It is an example of Acceleration.

There was change in velocity within the 10 minutes.
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<span>The change in the electron's potential energy is equal to the work done on the electron by the electric field. The electron's potential energy is the stored energy relative to the electron's position in the electric field. Vcloud - Vground represents the change in Voltage. This voltage quantity is given to be 3.50 x 10^8 V, with the electron at the lower potential. The formula for calculating the change in the electron's potential energy (EPE) is found by charge x (Vcloud - Vground) = (EPEcloud - EPE ground) where charge is constant = 1.6 x 10^-19. Filling in the known quantities results in the expression 1.6 x 10^-19 (3.50 x 10^8) = (EPEcloud - EPEground) = 5.6 x 10^-11. Therefore, the change in the electron's potential energy from cloud to ground is 5.6 x 10^-11 joules.</span>
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3 years ago
I just need x isolated
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Answer:

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

Explanation:

rx+y=\frac{t}{x}\\\\x(rx+y)=(\frac{t}{x})x\\\\rx^2+yx=t\\\\rx^2+yx-t=t-t\\\\rx^2+yx-t=0

Solve using the quadratic formula.

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

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