Answer:D
Explanation:
Given
Force required to move a box at steady rate is F=78 N
Weight of Block W=150 N
If the block is moving at a steady rate then net Force acting on it is zero
Applied Force must balance the Friction force
where N=normal Reaction
Normal reaction must be equal to weight
Answer:
Id = 1/2 Md * R^2 = 1/2 * .1 * .1^2 = .0005 kg m^2 inertia of disk
Ib = Mb * R^2 = .02 * .1^2 = .0002 kg m^2 inertia of bug at edge
(Id + Ib) w1 = Id w2 conservation of angular momentum
w2 = .0007 / .0005 * 10 = 14 /sec angular speed with bug at center
KE1 = 1/2 I1 * w1^2 = 1/2 * .0007 * 10^2 = .035 kg m^2 / s^2
KE2 = 1/2 * I2 w2*2 = (.0005 / 2 ) ^ 14^2 = .049 kg m^2 / s^2
The bug has to exert radial force on the disk to maintain its
centripetal acceleration. As the bug crawls to the center of the disk it
does work against this centripetal force which appears as an increase
of rotational energy of the disk. As the the bug crawls back to the edge
of the disk, the disk does work on the bug and loses KE.
<span>Longitudinal waves travel through a series of compression's and </span>rarefaction's.<span />
Answer:
gravitational potential energy
Explanation:
yeah that's true.........