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cestrela7 [59]
4 years ago
10

Object A with a mass of 1.5 kilograms is moving with a velocity of +11.2 meters/second (moving in the +x direction). It has a pe

rfectly elastic collision with stationary object B that has a mass of 4.5 kilograms. After the collision, object B travels with a velocity of +5.6 meters/second. What is the final velocity for object A?
Physics
2 answers:
IrinaK [193]4 years ago
5 0
Hi, the final velocity for object A is -5.6 m/s 
kolezko [41]4 years ago
3 0

Answer:

The final velocity for object A is 5.6 m/s in opposite direction.

Explanation:

Given that,

Mass of object A=1.5 kg

Initial velocity of Object A = 11.2 m/s

Mass of object B = 4.5 kg

Initial velocity of object B= 0 because object B is stationary

Final velocity of object B  = 5.6 m/s

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}....(I)

Where, m₁= mass of object A

u₁ = initial velocity of object A

v₁ = final velocity of object A

m₂= mass of object B

u₂ = initial velocity of object B

v₂ = final velocity of object B

we substitute the value in equation (I)

1.5\times11.2+0=1.5\times v_{1}+4.5\times 5.6

v_{1}=\dfrac{1.5\times11.2-4.5\times 5.6}{1.5}

v_{1}=-5.6\ m/s

Hence, The final velocity for object A is 5.6 m/s in opposite direction.

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A certain car battery with a 12.0 V emf has an initial charge of 131 A · h. Assuming that the potential across the terminals sta
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4 years ago
1. Two forces act on a box as follows: F1 = 100 N at 01 = 170° and F2 = 75 N
lilavasa [31]

Answer:

a)  F = 64.30 N,  b) θ = 121.4º

Explanation:

Forces are vector quantities so one of the best methods to add them is to decompose each force and add the components

let's use trigonometry

Force F1

          sin 170 = F_{1y} / F₁

          cos 170 = F₁ₓ / F₁

          F_{1y} = F₁ sin 170

          F₁ₓ = F₁ cos 170

          F_{1y} = 100 sin 170 = 17.36 N

          F₁ₓ = 100 cos 170 = -98.48 N

Force F2

          sin 30 = F_{2y} / F₂

          cos 30 = F₂ₓ / F₂

          F_{2y} = F₂ sin 30

          F₂ₓ = F₂ cos 30

          F_{2y} = 75 sin 30 = 37.5 N

          F₂ₓ = 75 cos 30 = 64.95 N

the resultant force is

X axis

          Fₓ = F₁ₓ + F₂ₓ

          Fₓ = -98.48 +64.95

          Fₓ = -33.53 N

Y axis

         F_y = F_{1y} + F_{2y}

         F_y = 17.36 + 37.5

         F_y = 54.86 N

a) the magnitude of the resultant vector

let's use Pythagoras' theorem

         F = Ra Fx ^ 2 + Fy²

         F = Ra 33.53² + 54.86²

         F = 64.30 N

b) the direction of the resultant

let's use trigonometry

        tan θ’= F_y / Fₓ

        θ'= tan^{-1}  \frac{F_y}{F_x}

        θ'= tan⁻¹ (54.86 / (33.53)

        θ’= 58.6º

this angle is in the second quadrant

The angle measured from the positive side of the x-axis is

        θ = 180 -θ'

        θ = 180- 58.6

        θ = 121.4º

5 0
3 years ago
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