Answer : The temperature when the water and pan reach thermal equilibrium short time later is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of aluminium = 
= specific heat of water = 
= mass of aluminum = 0.500 kg = 500 g
= mass of water = 0.250 kg = 250 g
= final temperature of mixture = ?
= initial temperature of aluminum = 
= initial temperature of water = 
Now put all the given values in the above formula, we get:
Therefore, the temperature when the water and pan reach thermal equilibrium short time later is,
Answer:
2452.79432 m/s
Explanation:
m = Mass of ice
= Latent heat of steam
= Specific heat of water
= Latent heat of ice
v = Velocity of ice
= Change in temperature
Amount of heat required for steam
Heat released from water at 100 °C
Heat released from water at 0 °C
Total heat released is
The kinetic energy of the bullet will balance the heat
The velocity of the ice would be 2452.79432 m/s
Answer:
Θ=0.01525 rad
or
Θ=0.87°
Explanation:
Given data
wavelength λ=2.5 µm =2.5×10⁻⁶m
Diameter d=0.20 mm =0.20×10⁻³m
To find
Angle Θ in radians and degree
Solution
Circular apertures have first dark fringe at
Θ=(1.22λ)/d
Substitute the given values
So
Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m
Θ=0.01525 rad
or
Θ=0.87°
Answer:
One observation would be the change in odor when observing the logs burning in a campfire and because of that a inference could be because a change in odor is occurring, a chemical change is happening to the logs (combustion).
A second observation would be that the wood being burned gave off smoke at first but then stopped and because of that a inference would be that the compound that were being burned creating the smoke was all evaporated from the wood.
