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Vanyuwa [196]
3 years ago
13

A car travels 15 kilometers west in 10 minutes. After reaching the destination, the car travels back to the starting point, agai

n taking 5 minutes. What is the average velocity of the car?
A. 0 meters/seconds
B. 1.0 meters/seconds
C. 1.5 meters/seconds
D. 2.0 meters/seconds
Physics
1 answer:
jeka943 years ago
5 0

Speed = (distance traveled) / (time to travel the distance).
 
Strange as it may seem, 'velocity' is completely different. 

Velocity doesn't involve the total distance traveled at all. 
Instead, 'velocity' is based on 'displacement' ... the distance
between the start-point and end-point, regardless of the route
taken to get there.  So the displacement in driving once around
any closed path is zero, because you end up where you started. 

Velocity =

           (displacement during some time)
divided by
            (time for the displacement)

AND the direction from the start-point to the end-point.


For the guy who drove 15 km to his destination in 10 min, and then
back to his starting point in 5 min, (assuming he returned by way of
the same 15-km route):

         Speed = (15km + 15km) / (10min + 5min)  =  (30/15) (km/min)

                                                                                 =  2 km/min.

        Velocity = (end location - start position) / (15 min)  =  Zero .

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3 years ago
What is the safety rules?
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Answer:

Quick question do you mean what are some safety rules

Explanation:

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3 years ago
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A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1
aivan3 [116]

Answer:

Part a)

F_n = 306 N

Part b)

v = 12.1 m/s

So this speed is independent of the mass of the rider

Explanation:

Part a)

By force equation on the rider at the position of the hump we can say

mg - F_n = ma_c

now we will have

mg - F_n = \frac{mv^2}{R}

F_n = mg - \frac{mv^2}{R}

now we have

F_n = 100(9.81) - \frac{100(9^2)}{12}

F_n = 981 - 675

F_n = 306 N

Part b)

At the top of the loop if the minimum speed is required so that it remains in contact so we will have

F_n + mg = ma_c

F_n = 0 at minimum speed

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{15 \times 9.81}

v = 12.1 m/s

So this speed is independent of the mass of the rider

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3 years ago
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Answer:

Explanation:

The work done is defined as the product of force applied in the direction of displacement and the displacement.

W = F x d x Cosθ

where, F is the force applied, d be the displacement and θ be the angle between the displacement and force.

For the normal forces, the angle between the displacement and the force applied is 90 degree, and the value of Cos 90 is zero, so the work done is zero.

3 0
3 years ago
Could someone help me with this question please?
BabaBlast [244]
You are correct...amplitude will be the answer
3 0
3 years ago
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