600 watts may be your answer:)
1.06 is the <u>maximum</u> refractive index that the liquid may have for the light to be totally reflected.
Only when a light source passes from a denser to a rarer medium can it completely reflect.
When the angle of incidence surpasses a specific critical value, specular reflection occurs in the more highly refractive of the two mediums at their interface, and this reflection is known as total reflection.
sin 
= μ
/ μ
From the diagram
Angle of incidence = 60°
sin60° ≥ sin = μ/μ
μ ≤ μ sin60°
μ ≤ √1.5 × √3/2
= 1.06
Hence, the maximum index that the liquid may have for the light to be totally reflected is 1.06
Learn more about refractive index here brainly.com/question/10729741
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Answer:
1) John's ball lands last.
2) All three have the same total energy
Explanation:
John's ball will land last because his ball was projected at the largest angle. This means that the ball will spend more time in the air when compared to the other balls.
The total energy in a projected particle is the sum of its kinetic energy (0.5mv^2) and its potential energy due to its height (mgh). The total kinetic energy can be as a result of both, or at times fully transformed to either of the energy. For example, at the maximum height, the kinetic energy of John's ball is zero and is fully transformed into potential energy due to that height, whereas George's ball will mostly posses kinetic energy and a little potential energy. The three ball are assumed to have the same properties and are projected with the same initial velocity. This means that they all have the same kinetic energy at the instance of projection which can then be transformed into potential energy, or maintained as a combination of both throughout the flight or simply transformed into potential energy, but the total energy is always conserved.
If you’re doing potential and kinetic energy then the answer is potential.
Two things that aren't involved in speed: -- the straight-line distance between the start- and end- points. -- the direction from start-point to end-point.
