Answer:
Empirical formula of the Tin oxide sample is SnO₂
Explanation:
Tin reacts with combines with oxygen to form an oxide of tin.
Mass of crucible with cover = 19.66 g
Mass of crucible, cover, and tin sample = 22.29 g
Mass of crucible and cover and sample, after prolonged heating gives constant weight = 21.76 g
Mass of Tin oxide sample = 22.29 - 19.66 = 2.63 g
Mass of ordinary tin, after heating to breakdown the tin and oxygen = 21.76 - 19.66 = 2.1 g
Meaning that, mass of oxygen in the tin oxide sample = 2.63 - 2.1 = 0.53 g
Mass of Tin in the Tin Oxide sample = 2.1 g
Mass of Oxygen in the Tin oxide sample = 0.53 g
Convert these to number of moles
Number of moles of Tin on the Tin oxide sample = 2.1/118.71 = 0.0177
Number of moles of Oxygen in the Tin oxide sample = 0.53/16 = 0.0335
divide the number of moles by the lowest number
0.0177:0.0335
It becomes,
1:2
SnO₂
Hence, the empirical formula for the Tin oxide sample = SnO₂
