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vladimir2022 [97]
3 years ago
12

An idea that is proven to be true after being tested over and over again then becomes a?

Physics
1 answer:
Minchanka [31]3 years ago
4 0
I believe it is C. Correct me if I’m wrong.
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(1) A positive charge +3 C is separated from another positive charge of +5 C by a distance of 7m. What is the magnitude of the e
Aneli [31]

1. The magnitude of the electric force between the two charges is 2.8×10⁹ N (Option B)

2. The net charge on the molecule is -8×10⁻¹⁹ C (Option D)

3. The magnitude of the force between the charges is 16000 N (Option C)

4. The correct statement is: A neutral object has equal numbers of protons and electrons. (Option C)

<h3>1. How to determine the force</h3>
  • Charge 1 (q₁) = +3 C
  • Charge 2 (q₂) = +5 C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 7 m
  • Force (F) =?

F = Kq₁q₂ / r²

F = (9×10⁹ × 3 × 5) / (7)²

F = 2.8×10⁹ N

<h3>2. How to determine the net charge on the molecule</h3>
  • Electron = 223 electrons
  • Proton = 218 protons
  • Net Charge =?

Charge = Proton - Electron

Charge = 218 - 223

Charge = -5 electrons

But

1 electron = 1.6×10⁻¹⁹ C

Thus,

Net Charge = -5 × 1.6×10⁻¹⁹ C

Net Charge = -8×10⁻¹⁹ C

<h3>3. How to determine the force</h3>
  • Charge 1 (q₁) = 2×10⁻⁴ C
  • Charge 2 (q₂) = 8×10⁻⁴ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.3 m
  • Force (F) =?

F = Kq₁q₂ / r²

F = (9×10⁹ × 2×10⁻⁴ × 8×10⁻⁴) / (0.3)²

F = 16000 N

<h3>4. What is a neutral object?</h3>

A neutral object is an object having equal numbers of protons and electrons. For example, an object with 4 protons and 4 electrons is said to be neutral as illustrated below

  • Electron = 4 electrons
  • Proton = 4 protons
  • Net Charge =?

Charge = Proton - Electron

Charge = 4 - 4

Charge = 0 (neutral)

Thus, the correct statement about neutral object, given in the question is: A neutral object has equal numbers of protons and electrons (Option C)

Learn more about Coulomb's law:

brainly.com/question/506926

#SPJ1

6 0
2 years ago
If a 126 gram marble rolls down a hill at an acceleration of 3.0m/s2, what would the force be on the marble?​
adelina 88 [10]

Answer:

Explanation:

Net force would be the one causing the acceleration or

F = ma = 0.126(3.0) = 0.378 N

4 0
3 years ago
A horizontal rope is tied to a 57.0 kg kg box on frictionless ice. What is the tension in the rope if: You may want to review (P
VARVARA [1.3K]

Answer:

Explanation:

A ) The surface is frictionless . If the box is at rest , there will be no tension in the rope.

B ) In this case , the box is moving with steady rate of 4.20 m /s . In this case also no force is acting on the box so tension in the rope will be nil.

C ) In this case the box is moving with acceleration of 5.8 m /s² so force on the box = mass x acceleration

= 57 x 5.8

= 330.6 N .

So tension in the rope will be equal to force acting on the rope . Hence tension = 330.6 N .

8 0
3 years ago
The atmospheric temperature decreases when snow starts melting because the snow releases thermal energy from the atmosphere to m
Sergeeva-Olga [200]

Answer:

This assertion is false

Explanation:

It can be a said that when snow melts to liquid, then at that phase certain amount of energy was needed to change it from its solid state to liquid. The energy needed is given as:

Q=mL

Where m is the mass of snow.

L is latent heat of fusion.

So when there is the melting of snow from solid to liquid, thermal energy gotten from the surrounding gets absorbed so as to convert it into liquid phase.

5 0
3 years ago
Read 2 more answers
A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it
Svetach [21]

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.

So

<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)

<em>v</em>² = 4645 m²/s²

<em>v</em> ≈ 68.15 m/s

5 0
4 years ago
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