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vladimir2022 [97]
3 years ago
12

An idea that is proven to be true after being tested over and over again then becomes a?

Physics
1 answer:
Minchanka [31]3 years ago
4 0
I believe it is C. Correct me if I’m wrong.
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A spherical shell with a net charge of 3Q surrounds a point charge of -q at the center of the shell. The charges on the inner an
aleksley [76]

Answer:

1) The charge on the outer shell is +4·Q

2) The charge on the inner shell is +Q

Explanation:

1) The given parameters of the spherical shell are;

The net charge on the spherical shell = 3·Q

The point charge surrounded by the spherical shell = -Q

Let 'x' represent the charge on the outer shell, and let 'y', represent the charge on the inner shell, we have;

The net charge, 3·Q = -q + x

∴ x = 3·Q + Q = 4·Q

The charge on the outer shell, x = 4·Q

2) The net charge in the shell is zero, therefore, the charge on the inner shell, 'y', is given as follows;

-Q + y = 0

∴ y = +Q

The charge on the inner shell, y = +Q

5 0
3 years ago
A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a
il63 [147K]

Answer:

0.0000109261200583 s

0.0109261200583

Explanation:

d_2 = Distance from right ear = 3 m

s = Distance between ears = 15 cm

v = Speed of sound in air = 343 m/s

Distance between the left ear and the bird

d_1=\sqrt{s^2+d_2^2}\\\Rightarrow d_1=\sqrt{0.15^2+3^2}\\\Rightarrow d_1=3.00374765918\ m=3.004\ m

Time

t=\dfrac{Distance}{Speed}

Time difference would be

\Delta T=\dfrac{d_1}{v}-\dfrac{d_2}{v}\\\Rightarrow \Delta T=\dfrac{3.00374765918}{343}-\dfrac{3}{343}\\\Rightarrow \Delta T=0.0000109261200583\ s

The time difference is 0.0000109261200583 s

Time period is given by

T=\dfrac{1}{f}\\\Rightarrow T=\dfrac{1}{1000}\\\Rightarrow T=10^{-3}\ s

The ratio is

\dfrac{\Delta T}{T}=\dfrac{0.0000109261200583}{10^{-3}}\\\Rightarrow \dfrac{\Delta T}{T}=0.0109261200583

The ratio is 0.0109261200583

7 0
3 years ago
Rachel collected data on the speed of sound waves passing through different media.
Helga [31]

The conclusion is, medium Q is most likely a solid because solids have the highest density and sound waves travel fastest in high density media.

<h3>Effect of density on speed of sound</h3>

Sound wave is mechanical wave that requires material medium for its propagation.

A high dense medium, is a medium with closely packed molecules. Since sound wave requires material medium for its propagation, it will travel faster in a high dense medium than a less dense medium.

Thus, the speed of sound increases as the density of the medium increases.

<h3>Speed of sound in the different media</h3>

The conclusion that can be made from the speed of sound in the different media is "Medium Q is most likely a solid because solids have the highest density and sound waves travel fastest in high density media".

Learn more about effect of density on speed of sound here: brainly.com/question/3323620

7 0
2 years ago
Please help!
Yanka [14]

Answer:

V=3.57 × 10^6 m/s

hope it is helpful..

7 0
3 years ago
How many millimeters are in 8 meters?
frutty [35]

Explanation:

8 m × (1000 mm / m) = 8000 mm

3 0
3 years ago
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