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adell [148]
3 years ago
6

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is

3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds) 5.50 × 10-11 Hz 2.39 × 10-50 Hz 5.45 × 1018 Hz 1.633 × 1027 Hz
Physics
2 answers:
Tpy6a [65]3 years ago
8 0
Energy (E) = Planck's constant (h) * frequency (nu)
3.611*10^{-15}J = 6.626 * 10^{-34} * frequency
therefore, frequency ~ 5.45*10^{18}
Dennis_Churaev [7]3 years ago
3 0

Answer:

Energy (E) = Planck's constant (h) * frequency (nu)

3.611*10^{-15}J = 6.626 * 10^{-34} * frequency

therefore, frequency ~ 5.45*10^{18}

Explanation:

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What is the difference between a radiological weapon and a nuclear weapon?
AVprozaik [17]

What is the difference between the nuclear material in a bomb, versus a reactor? A nuclear reactor works by using the energy that is released when the nucleus of a heavy atom splits. That process is called fission. In reactors, fission occurs when uranium atoms are hit by slow-moving neutrons.

6 0
3 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
A tank containing 200 L of hydrogen gas at 0.0 Celsius is kept at 10 kPa. The pressure is raised to 95C, and the volume is decre
dybincka [34]

Answer:

The new pressure of the gas is 15.40 kPa.

Explanation:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Mathematically this law indicates that the quotient between pressure and temperature is constant:

\frac{P}{T}=k

On the other hand, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as:

P*V=k

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. Mathematically, this law says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

Studying an initial state 1 and a final state 2, it is fulfilled:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1= 10 kPa
  • V1= 200 L
  • T1= 0 C= 273 K
  • P2=?
  • V2= 175 L
  • T2= 95 C= 368 K

Replacing:

\frac{10 kPa*200 L}{273 K}=\frac{P2*175 L}{368 K}

Solving:

P2=\frac{368 K}{175 L} *\frac{10 kPa*200 L}{273 K}

P2= 15.40 kPa

<u><em>The new pressure of the gas is 15.40 kPa.</em></u>

6 0
3 years ago
A 70kg skier moving at 5 m/sec down a slope what is the skier’s momentum
olga2289 [7]

<u><em>Answer:</em></u>

Momentum of the skier is 350 Kg.m/sec

<u><em>Explanation:</em></u>

<u>Momentum of a body can be calculated using the following rule:</u>

P = m * v

<u>where:</u>

P is the momentum of the body

m is the mass of the body given as 70 Kg

v is the velocity of the body given as 5 m/sec

<u>Substitute with the givens in the above rule to get the momentum of the skier as follows:</u>

P = m * v

P = 70 * 5

P = 350 Kg.m/sec

Hope this helps :)

4 0
3 years ago
Guiana dolphins are one of the few mammals able to detect electric fields. In a test of sensitivity, a dolphin was exposed to th
Y_Kistochka [10]

Answer:

0.05 V/m

Explanation:

For a uniform electric field, electric field strength and potential difference are related by

E=\frac{\Delta V}{d}

where

E is the electric field strength

\Delta V is the potential difference

d is the distance between the two points

Here we have

\Delta V= 0.50 mV=5\cdot 10^{-4}V

d=1.0 cm=0.01 m

So, the electric field strength is

E=\frac{5\cdot 10^{-4} V}{0.01 m}=0.05 V/m

3 0
3 years ago
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