There’s 1,000 grams per liter. I’ll help you out by giving you the formula.
0.50L over 5.00 M= 1,000grams over one liter
Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1 = 1000L
Multiply by 1000 to convert to L/s
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt (X) is contained in 2,592,000,000L/day
X=
X= 129,600,000,000 mg/day
convert this value to kg/day by multiply by
X= 129,600kg/day
Answer:
The amount of oxygen in 2.5 moles of water is 40 grams. The molecular formula of water is H₂O. 1 mole of water contains 1 mole of oxygen
Answer:
a. MgO(s) + H2CO3(aq) → MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.
b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.
c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.
d. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(1) COMBUSTION REACTION.
e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.
f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.
Answer:
moles of water in 1 ml = 1/18 mol.
take 1 ml and calculate it by 30
1 ml x 30= 30 ml
Explanation: