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3 years ago

When K-37 undergoes positron emission, what is the resulting atom?

Chemistry

1 answer:

natita [175]3 years ago

4 0

Answer:

C) Ar-37

Explanation:

A positron is a positively charged electron. It has the same mass as that of an electron, but opposite charge. It is the counterpart of an electron.

The reaction involving the emission of a positron by k-37 would produce a Ar-37, which is an unstable isotope of Argon. In this emission, there must not be a particle loss or creation, the addition of the mass number and proton number on LHS must be the sane as that on RHS of the equation.

An isotope is ability of an element to exist in two or more forms with the same atomic number but different mass number.

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Nuclear energy can be used to power _______. a. street lights b. businesses c. homes d. all of the above Please select the best

Taya2010 [7]

<h3><u>Answer;</u></h3>

All the above

-street lights

-businesses

- Homes, etc

<h3><u>Explanation; </u></h3>

Nuclear energy comes from splitting atoms in a reactor to heat water into steam, turn a turbine and generate electricity.
Nuclear reactions are used to release nuclear energy that generate heat, which most frequently is then used in steam turbines to produce electricity in a nuclear power plant.
Because nuclear power plants do not burn fuel, they do not produce greenhouse gas emissions.
Nuclear energy may be used in a wide variety of fields as it generates high levels of electricity without causing damage to our environment and atmosphere.

8 0

3 years ago

In the final stage of the nuclear fuel cycle, the spent fuel must be transported, processed, and disposed of properly. True Fals

Aleksandr [31]

True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal.

8 0

3 years ago

Read 2 more answers

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 412.072 \ g \ Cl_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

5 0

3 years ago

Toothpaste contains Sodium fluoride which is used to prevent tooth decay. How many grams are in 1 mole NaF?

nikitadnepr [17]

The answer is 42 grams of NaF are there in 1 mole.

A mole is defined as 6.022 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance.

Molar Mass , i.e. mass of 1 mole of NaF is sum of molar mass of Na and F

23 + 19

42 grams

Therefore 42 grams of NaF Sodium-fluoride are there in 1 mole.

To know more about mole

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6 0

2 years ago

The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the rea

sineoko [7]

We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula:
Kc = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 = 0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

4 0

3 years ago