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3 years ago

When K-37 undergoes positron emission, what is the resulting atom?

Chemistry

1 answer:

natita [175]3 years ago

4 0

Answer:

C) Ar-37

Explanation:

A positron is a positively charged electron. It has the same mass as that of an electron, but opposite charge. It is the counterpart of an electron.

The reaction involving the emission of a positron by k-37 would produce a Ar-37, which is an unstable isotope of Argon. In this emission, there must not be a particle loss or creation, the addition of the mass number and proton number on LHS must be the sane as that on RHS of the equation.

An isotope is ability of an element to exist in two or more forms with the same atomic number but different mass number.

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Convert each of the measurements given to the new unit stated using the factor label method (dimensional analysis). Show all wor

Diano4ka-milaya [45]

26 cm -0.26 m

4 hr - 240 min

3.25 km -3250 m

5 ft -60 inches

3 0

3 years ago

what’s the chemical equation for production of potassium vapor and molten sodium chloride from molten potassium chloride and mol

elena-14-01-66 [18.8K]

Answer:

$\huge\boxed{\sf KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}}$

Explanation:

<u>Chemical formulas for every compound:</u>

Potassium vapor => $K_{(l)$

Molten soldium chloride => $NaCl_{(aq)}$

Molten Potassium chloride => $KCl_{(aq)}$

Molten Sodium Metal => $Na_{(aq)}$

<u>The reaction will be as follows:</u>

$KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}$

This reaction is usually called displacement reaction in which an element displaces another element of a compund.

$\rule[225]{225}{2}$

4 0

2 years ago

Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g

Katen [24]

Percentage yield=(actual yield/theoretical yield) x 100%
= (45/50) x 100%
= 90%

8 0

3 years ago

Since acids have 1 more proton (H+ - ions) than base, and the acid gives it away, doesn't that mean that they switch roles? Acid

andreev551 [17]

Answer:

In an acid-base equilibrium, acid becomes a conjugate base and base becomes a conjugate acid.

Explanation:

Let's remember the Bronsted-Lowry theory to answer this specific question. According to the theory, acid is a proton donor, while a base is a proton acceptor.

Consider an acid in a form HA (aq) and base in a form of B (aq). Since acid is a proton donor, it will donate its hydrogen ion to the base, B. The resultant products would be $A^{-}$ (aq) and $BH^{+}$ (aq).

Remember that an acid-base reaction is an equilibrium reaction. This means we may also look at this proton transfer reaction from the product side towards the reactants. Summarizing what has been said, we may write the equilibrium as:

$HA (aq) + B (aq)$ ⇄ $BH^{+} (aq) + A^{-} (aq)$

Now acid, HA, donates a proton to become a conjugate base. The conjugate base, if we look from the reverse equation side, is actually a base, since it can accept a proton to become HA. Similarly, B accepts a proton to become a conjugate acid. Looking from the reverse reaction, it can now donate a proton, so in reality we can consider it a base.

To summarize, your logic is correct.

6 0

3 years ago

2. Which substance has the greatest molecular

storchak [24]

Answer:

Choice 4 easy

Explanation:

4 0

2 years ago