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PolarNik [594]
4 years ago
14

The temperature of aluminum increases from 30 to 38 degrees Celsius and absorbed 900J. Calculate the mass of aluminum used if th

e specific heat is 0.902 J/g K.
Physics
1 answer:
garri49 [273]4 years ago
8 0

Answer: 3.99g

Explanation:

Specific heat capacity (c) is defined as the quantity of heat required to raise the temperature of an object/ a body by 1kelvin.

Mathematically, Q = mc∆t where;

Q is the quantity of heat absorbed

m is the mass of the object

c is the specific heat capacity

∆t is the change in temperature = final temperature - initial temperature.

Given Q = 900Joules, c =0.902J/gK ∆t = 38°C - 30°C = 8°C = 8°C+273 = 281Kelvin

m is the unknown

Substituting this values in the given formula to get m we have;

m = Q/c∆t

m = 900/0.802(281)

m = 900/225.362

m = 3.99g

Mass of aluminum used is 3.99g

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Answer:

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s=384 mts

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16t^2-160t+384=0

 

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In Millikan's oil drop experiment an oil drop is at rest between two large plates separated by 1.3 cm when the potential differe
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Mass of the oil drop, m=3.01\times 10^{-15}\ kg

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