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3 years ago

What is the speed of a car that travels a distance of 520 kilometers in 12 hours?

2 answers:

8 0

You need to find the distance traveled in one hour. To find this, divIf the total distance by the total time. 520/12=43.3 km an hour. Hope this helps! ;)

Effectus [21]3 years ago

7 0

Answer:

v= 43.3 km/ h

Explanation:

kinematics of the car

We apply the formula for calculating the speed (v):

v = d / t Formula (1)

Where:

v= speed in kilometers per hour (km/h)

d: distance in meters (km)

t: time in hours (h)

Data

d=520 km

t= 12 h

Problem development

We replace data in the formula (1)

v = d / t = 520 km / 12 h

v= 43.3 km/h

Car speed is 43.3 km / hr

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A solid iron ball of mass 770 kg is used on a building site. The ball is suspended by a rope from a crane. The distance from the

Scrat [10]

From a balistics pendulum as an example, which is probably where you are at... Triangles, L = 12m, x_0 = 1.6, we need to find the angle (theta) sin (theta) = 1.6/12 = 0.1333.... theta = ArcSin(0.1333...) = 0.1337 rad Then, this is the height that the mass vertically raises in it's arc y_2 = L-L*cos(theta) = 0.107 m use y_2 in a kinematic swing... <span><span>v=sqrt(<span><span>2g<span>y_2)</span></span></span>=1.45m/s</span></span>

6 0

4 years ago

Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s

muminat

Answer:

Acceleration = 10.06 m/s²

Explanation:

1 mile = 1.6093km

1609.3m = 1 mile

1 m = $\frac{1}{1609}$ mile

50.0 miles/hour = $\frac{50 * 1609.3}{60 * 60}$ m/s

= 22.35m/s

from equation

S = Ut + 1/2 at²

v = U + at

22.35 = 0 + a * 2.22

a = 22.35 ÷ 2.22

= 10.06 m/s²

4 0

3 years ago

A 10.0-kg mass is placed on a 25.0o incline and friction keeps it from sliding. The coefficient of static friction in this case

vovangra [49]

The frictional force while the mass is sliding will be 46.2 N.

<h3>What is friction force?</h3>

Opposition forces on the surface cause heat loss during the motion of an object known as the friction force.

Given data:

m(mass)= 10.0-kg

Θ (Inclination angle)=25.0o

Coefficient of sliding friction, $\rm \mu_k$ =0.520

Coefficient of static friction, $\rm \mu_s=0.520$

The friction force, F=?

Resolve the force in the inclined plane;

$\rm F=\mu_s mg cos25^0 \\\\ F=0.520 \times 10 \times 9.81 \times cos 25 ^0 \\\\ F= 46.2 \ N$

Hence, the frictional force while the mass is sliding will be 46.2 N.

To know more about friction force refer to the link;

brainly.com/question/1714663

#SPJ1

5 0

2 years ago

A flat disk of radius 0.50 m is oriented so that the plane of the disk makes an angle of 30 degrees with a uniform electric fiel

nexus9112 [7]

Answer:

The electric flux is $280\ \rm N.m^2/C$

Explanation:

Given:

Radius of the disc R=0.50 m
Angle made by disk with the horizontal $\theta=30^\circ$
Magnitude of the electric Field $E=713.0\ \rm N/C$

The flux of the Electric Field E due to the are dA in space can be found out by using Gauss Law which is as follows

$\phi=\int E.dA$

where

$\phi$ is the total Electric Flux
E is the Electric Field
dA is the Area through which the electric flux is to be calculated.

Now according to question we have

$=EA\cos\theta \\=713\times 3.14\times 0.5^2 \times \cos60^\circ\\=280\ \rm N.m^2/C$

Hence the electric flux is calculated.

8 0

3 years ago

# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah

yan [13]

Answer:

Explanation:

Solution,

When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 72 km/h ( Given)

We have to convert 72 km /h in m/s

$72 \: km \: per \: hour$

$= 72 \times \frac{1000}{60 \times 60}$

$= 20$ m/s

Final velocity ( v ) = 20 m/s

Time taken ( t ) = 2 seconds

Acceleration (a) = ?

Now,

we have,

$a = \frac{v - u}{t}$

$a = \frac{20 - 0}{2}$

$a = \frac{20}{2}$

$a = 10$ m/s ^2

Hope this helps...

Good luck on your assignment..

7 0

3 years ago