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Lesechka [4]
3 years ago
14

You're outside on a cold day (Tout = 0 °C)listening to your iPod with an external circular speaker having a diameter 0.0550 m. B

ecause of the cold you decide to go inside where the temperature is 27.5 °C. If your favorite song begins with a 8.54-kHz tone, find the change in the diffraction angle of this tone assuming the air behaves as an ideal gas.
Physics
1 answer:
JulijaS [17]3 years ago
8 0
1). The change would be due to the expansion of the speaker, so we need to know what substances comprise the speaker. #2). A speaker with a diameter of 0.055m is not too good at reproducing 8.54 KHz. (3). I believe this is a bogus question.
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if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​
Likurg_2 [28]

Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s

6 0
3 years ago
Why are insulators important?
GenaCL600 [577]

Answer:

An insulator opposes the flow of electricity. Insulators are important to keep us safe from electricity. The wire that carries electricity to your computer or television is covered with a rubber-like insulator that protects you from getting electrocuted. Good insulators include glass, the air, and paper.

Explanation:

Hope this helped, Have a Wonderful Day!!

8 0
3 years ago
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True or False: If the initial speed of an object is zero, then the initial position of the object must be the origin. Explain
lions [1.4K]

Answer:

False

Explanation:

It is not necessary, that when the initial speed of the object is zero then it must be at origin.

It may be the object starts motion from the left of origin.

4 0
3 years ago
You pull downward with a force of 27.3 N on a rope that passes over a disk-shaped pulley of mass 1.43 kg and radius 0.0792 m. Th
Salsk061 [2.6K]

Answer:

The tension in the left side string = 17.21 N

The tension in the right side string = F = 27.3 N

Explanation:

Given that

F= 27.3 N

M= 1.43 kg ,r= 0.0792 m

Moment of inertia of disk ,I = 0.5 m r²

I = 0.5 x 1.43 x 0.0792² = 0.0044 kg.m²

m= 0.7 kg

Lets take linear acceleration of system is a m/s²

Lets take tension in left side string = T

From Newtons law

T- mg = ma  

T- 0.7 x 10 = 0.7 a  ----------1

(F - T) r = I α      

α = Angular acceleration of disk

a = α  r

(F - T) r = I α  

(F - T) r² = I a  

( 27.3 - T) x 0.0792² = 0.0044 a        --------2

Form equation 1 and 2

a= 1.42 T - 10 m/s²

a = 1.42 ( 27.3 - T)  m/s²

1.42 T - 10 = 38.9 - 1.42 T

T=17.21 N

The tension in the right side string = F = 27.3 N

5 0
3 years ago
Please help with Physics Circuits!
Zigmanuir [339]
1) Let's start by calculating the equivalent resistance of the three resistors in parallel, R_2, R_3, R_4:
\frac{1}{R_{234}}= \frac{1}{R_2}+ \frac{1}{R_3}+ \frac{1}{R_4}= \frac{1}{4.5 \Omega}+ \frac{1}{1.3 \Omega}+ \frac{1}{6.3 \Omega}=1.15 \Omega^{-1}
From which we find
R_{234}= \frac{1}{1.15 \Omega^{-1}}=0.9 \Omega

Now all the resistors are in series, so the equivalent resistance of the circuit is the sum of all the resistances:
R_{eq}=R_1 + R_{234} = 5 \Omega + 0.9 \Omega = 5.9 \Omega
So, the correct answer is D) 


2) Let's start by calculating the equivalent resistance of the two resistors in parallel:
\frac{1}{R_{23}} =  \frac{1}{R_2}+ \frac{1}{R_3}= \frac{1}{5 \Omega}+ \frac{1}{5 \Omega}= \frac{2}{5 \Omega}
From which we find
R_{23} = 2.5 \Omega

And these are connected in series with a resistor of 10 \Omega, so the equivalent resistance of the circuit is
R_{eq}=10 \Omega + 2.5 \Omega = 12.5 \Omega

And by using Ohm's law we find the current in the circuit:
I= \frac{V}{R_{eq}}= \frac{9 V}{12.5 \Omega}=0.72 A
So, the correct answer is C).


3) Let' start by calculating the equivalent resistance of the two resistors in parallel:
\frac{1}{R_{23}} =  \frac{1}{R_2}+ \frac{1}{R_3}= \frac{1}{5 \Omega}+ \frac{1}{5 \Omega}= \frac{2}{5 \Omega}
From which we find
R_{23} = 2.5 \Omega
Then these are in series with all the other resistors, so the equivalent resistance of the circuit is
R_{eq}=R_1 + R_{23}+R_4 = 5 \Omega + 2.5 \Omega + 5 \Omega =12.5 \Omega

And by using Ohm's law we find the current flowing in the circuit:
I= \frac{V}{R_{eq}}= \frac{12 V}{12.5 \Omega}=0.96 A

And so the voltage read by the voltmeter V1 is the voltage drop across the resistor 2-3:
V= I R_{23} = (0.96 A)(2.5 \Omega)=2.4 V
So, the correct answer is D).


4) Again, let's start by calculating the equivalent resistance of the two resistors in parallel:
\frac{1}{R_{23}} = \frac{1}{R_2}+ \frac{1}{R_3}= \frac{1}{13 \Omega}+ \frac{1}{18 \Omega}=0.13 \Omega^{-1}
From which we find
R_{23} = 7.55 \Omega

Now all the resistors are in series, so the equivalent resistance of the circuit is:
R_{eq}= R_1 + R_{23}+R_4=8.5 \Omega+7.55 \Omega + 3.2 \Omega = 19.25 \Omega

The current in the circuit is given by Ohm's law
I= \frac{V}{R_{Eq}}= \frac{15 V}{19.25 \Omega}=0.78 A

Now we can compare the voltage drops across the resistors. Resistor 1:
V_1 = I R_1 = (0.78 A)(8.5 \Omega)=6.63 V
Resistor 2 and resistor 3 are in parallel, so they have the same voltage drop:
V_2 = V_3 = V_{23} = I R_{23} = (0.78 A)(7.55 \Omega)=5.89 V
Resistor 4:
V_4 = I R_4 = (0.78 A)(3.2 \Omega)=2.50 V

So, the greatest voltage drop is on resistor 1, so the correct answer is D).


5) the figure shows a circuit with a resistor R and a capacitor C, so it is an example of RC circuit. Therefore, the correct answer is D).

6) The circuit is the same as part 4), so the calculations are exactly the same. Therefore, the power dissipated on resistor 3 is
P_3 = I_3^2 R_3 =  \frac{V_3^2}{R_3}= \frac{(5.89 V)^2}{18 \Omega}=2.0 W
So, correct answer is B).

7) The circuit is the same as part 4), so we can use exactly the same calculation, and we immediately see that the resistor with lowest voltage drop was R4 (2.50 V), so the correct answer is B) R4.
5 0
3 years ago
Read 2 more answers
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