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Kazeer [188]
3 years ago
10

How many days will pass between a new moon and a full moon?

Chemistry
2 answers:
Nimfa-mama [501]3 years ago
8 0

Answer:

30

Explanation:

im smart

vampirchik [111]3 years ago
6 0

Answer:

The longest duration between full moon to new moon (or new moon to full moon) lasts about 15 days and 14.5 hours, while the shortest duration between full moon to new moon (or new moon to full moon) lasts only about 13 days and 22.5 hours. New Moon appears higher on summer solstice than on winter solstice.

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What is the purpose of control set up
Archy [21]
The purpose<span> of preparing </span>Set-up<span> _ is to act as a </span>control set-up<span> to ensure that the (measured variable) is only caused by the(changed variable) and not any other variables in the experiment.</span>
3 0
3 years ago
How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?
Neporo4naja [7]
By  use  of  ideal  gas  equation   PV=  nRT     where  n  is  the  number  of  moles,P =  pressure, V   =  volume,  R=  gas  constant  (0.08206 L. atm/ mol.k)     ant  T  is  the  temperature,  

to  calculate  the  number  of  moles(n) =PV/RT

convert  ml  to L,  that  is  200/1000= 0.2  L

convert  mmHg  to  atm,  that  is  780mm hg  x  1atm/  760  mm  hg=  1.026  atm

convert  temperature  to   kelvin,  that  is 135  +273=  408  k
n  is  therefore=  (0.2  x   1.026)/ ( 0.08206  x   408)=  6.129  x10^-3   moles

from  avogadro  constant    1moles  =  6.02  x10^23  molecules   what  about  6 .129  x10^-3  moles

= ( 6.02  x10^23)  x (6.129 x10^-3)/  1mole =  3.69  x10^21  molecules
8 0
3 years ago
Calculate the wavelength of the photon emitted when an electron makes a transition from n=6 to n=3. You can make use of the foll
Angelina_Jolie [31]

<u>Answer:</u> The wavelength of light is 1.094\times 10^{-6}m

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Final energy level = 3

n_i = Initial energy level = 6

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{6^2} \right )\\\\\lambda =\frac{1}{914617m^{-1}}=1.094\times 10^{-6}m

Hence, the wavelength of light is 1.094\times 10^{-6}m

6 0
4 years ago
How do you figure out the # of<br> neutrons?
Colt1911 [192]

Answer:

Subtracting the number of protons from the atomic mass.

5 0
3 years ago
Read 2 more answers
Name the two products formed when hydrocarbons burn in oxygen​
Sergeu [11.5K]

Answer:

<em>Carb</em><em>on</em><em> </em><em>dio</em><em>xide</em><em> </em>(co2)

<em>Wate</em><em>r</em><em> </em><em>(</em><em>H2O</em><em>)</em>

8 0
2 years ago
Read 2 more answers
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