Answer:
Refer to the attachment for the diagram.
3.53 m/s.
Explanation:
Acceleration is the first derivative of velocity relative to time. In other words, the acceleration is the same as the slope (gradient) of the velocity-time graph. Let represents the time in seconds and
the speed in meters-per-second.
For :
- Initial value of
:
at
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
.
- Find the equation of this segment in slope-point form:
.
Similarly, for :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
. There's no acceleration. In other words, the velocity is constant.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
. In other words, the velocity is decreasing.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
- Find the equation of this segment in slope-point form:
.
is in the interval
. Apply the equation for that interval:
.
