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hammer [34]
3 years ago
7

A block of ice with mass mA rests on a wedge of ice with mass mB=7.93 kg that is cut so that the surface of the wedge makes an a

ngle of 37.5 with the ground. There is no friction between the pieces of ice or between the ice and the ground. At time t=0 the blocks are released from rest. What is the acceleration of mA in the direction parallel to the ground.
Physics
1 answer:
Alika [10]3 years ago
3 0

Answer:

The answer is 7.52 m/s².

Explanation:

To determine acceleration, N = Ma×g ÷ cos Ф

N sin Ф = ma

a = g Tan Ф m/s²

g = 9.8 m/s² and Ф = 37.5° ( angle for the velocity and gravitational force)

so, a = 9.8 × tan (37.5°)

Acceleration has to be determined in order to get the final answer.

a = 7.5198 m/s²

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A boxer can hit a heavy bag with great force. Why can't he hit a piece of tissue paper in midair with the same amount of force?
12345 [234]

Answer:

This is due to impulse

Explanation:

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You can set these equal as mΔv = FΔt

When a boxer punches a tissue, it is like punching a cushion or a pillow. The time that the hit takes is much grater than if they were to hit something solid. In addition, the change in velocity of the boxer's arm would be much greater when they hit a punching bag. In this equation, the greater the time, the less force that is needed.

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3 years ago
g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

\frac{da}{dr} = -2\frac{GM}{r^3}

da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

F_w = ma

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})

dF_W = -0.3N

Therefore there is a weight loss of 0.3N every kilometer.

4 0
3 years ago
An arch carries the thrust of weight to its _____(1)______. With a _____(2)______, the horizontal part of the structure supports
finlep [7]

Option D is correct. An arch carries the thrust of weight to its <u>sides </u>with a <u>post-and-lintel.</u>

<u></u>

<h3>What is an arch?</h3>

An arch is indeed a vertical curving construction that covers an elevated space that may or may not sustain the load above it or the pressure gradient against it

In the case of a horizontally arched, such as an embankment dam. While arches and vaults are often confused, A vault is defined as an ongoing arch forming a roof.

Option D satisfies the fill-in blanks option.

Hence option D is correct. An arch carries the thrust of weight to its <u>sides </u>with a <u>post-and-lintel.</u>

<u></u>

To learn more about the arch refer to the link;

brainly.com/question/18162421

6 0
2 years ago
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