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ra1l [238]
3 years ago
7

Write the formula for compound formed between pb^2+O^2

Chemistry
1 answer:
Zarrin [17]3 years ago
7 0
Its what the formula of a coupon between PB to plus plus to
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Write a balanced chemical equation (smallest integer coefficients possible) for the reaction between an acid and a base that lea
11Alexandr11 [23.1K]

Answer:

2HClO4(aq) + Ca(OH)2(aq) → Ca(ClO4)2(aq) + 2H2O(l)

Perchloric acid + Calcium hydroxide → Calcium perchlorate + Water.

Explanation:

This is a neutralization reaction where the acid, Perchloric acid reacts completely with an appropriate amount of base, aqueous Calcium hydroxide to produce salt, aqueous Calcium perchlorate and water, liquid H2O only.

During this reaction, the hydrogen ion, H+, from the HClO4 is neutralized by the hydroxide ion, OH-, from the Ca(OH)2 to form the water molecule, H2O.

Thus, it is called a neutralization reaction.

6 0
3 years ago
1.) The process for converting ammonia to nitric acid involves the conversion of NH3 to
Firdavs [7]

Answer:

a) 1.39 g ; b) O₂ is limiting reactant,  NH₃ is excess reactant; c) 0.7 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

MM:        17.03    32.00     30.01

              4NH₃  +  5O₂ ⟶ 4NO + 6H₂O

Mass/g:    1.5        1.85

2. Calculate the moles of each reactant  

\text{moles of NH}_{3} = \text{1.5 g NH}_{3} \times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}} = \text{0.0881 mol NH}_{3}\\\\\text{moles of O}_{2} = \text{1.85 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.057 81 mol O}_{2}

3. Calculate the moles of NO we can obtain from each reactant

From NH₃:

The molar ratio is 4 mol NO:4 mol NH₃

\text{Moles of NO} = \text{0.0881 mol NH}_{3} \times \dfrac{\text{4 mol NO}}{\text{4 mol NH}_{3}} = \text{0.0881 mol NO}

From O₂:

The molar ratio is 4 mol NO:5 mol O₂

\text{Moles of NO} =  \text{0.057 81 mol O}_{2}\times \dfrac{\text{4 mol NO}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NO}

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO.

The excess reactant is NH₃.

5. Calculate the mass of NO formed

\text{Mass of NO} = \text{0.046 25 mol NO}\times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \textbf{1.39 g NO}

6. Calculate the moles of NH₃ reacted

The molar ratio is 4 mol NH₃:5 mol O₂

\text{Moles reacted} = \text{0.057 81 mol O}_{2} \times \dfrac{\text{4 mol NH}_{3}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NH}_{3}

7. Calculate the mass of NH₃ reacted

\text{Mass reacted} = \text{0.046 25 mol NH}_{3} \times \dfrac{\text{17.03 g NH}_{3}}{\text{1 mol NH}_{3}} = \text{0.7876 g NH}_{3}

8. Calculate the mass of NH₃ remaining

Mass remaining = original mass – mass reacted = (1.5 - 0.7876) g = 0.7 g NH₃

8 0
3 years ago
Which of the statements about elements is true?
Jet001 [13]

1. No two elements have the same kind of atom.

Explanation:

The correct of all statement is that no two elements have the same kind of atoms.

Every element have different atoms.

  • Over a hundred elements have been identified by scientists.
  • Atoms are the smallest particles that takes part in chemical reactions.
  • Elements are distinct substances that cannot be split.
  • Atoms of all elements do not have the same mass and volume. Isotopes are examples.
  • It is true that atoms of all elements have different masses and also different volumes.
  • The volume of an atom is function of the number of electrons it contains.

learn more:

Dalton model of the atom brainly.com/question/1979129

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
What are some of the body's internal defenses
Amanda [17]
What are some of the body's internal defenses. The skin helps protect stuff to!
5 0
3 years ago
Read 2 more answers
Multiple choice
mihalych1998 [28]

Answer:

S + 4 Cl2

Explanation:

Sulphur - S

1 mol of Sulphur = S

Chlorine = Cl2

4 moles of Chlorine = 4Cl2

4S + 2Cl2

Incorrect option

S + 4 Cl2

Correct option

S + 2Cl2

Incorrect option

S + Cl2

Incorrect option

7 0
3 years ago
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