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4 years ago

Which element is placed in the same period as ruthenium but has a higher atomic number than it

2 answers:

8 0

Since it is in period five, any element that has a higher atomic number than it could be an answer, therefore, silver, bismuth, and osmium are possibilities.

Klio2033 [76]4 years ago

6 0

Answer:

The answer is Silver.

Explanation:

The complete question is:

"Which element is placed in the same period as ruthenium but has a higher atomic number than it? bismuth osmium silver zirconium"

In the periodic table the elements are arranged so that those with similar chemical properties are located close to each other.

The horizontal rows of the periodic table are called periods. The elements that make up the same row have different properties but similar masses: all the elements of a period have the same number of orbitals. In other words, the period that an element occupies coincides with its last electronic layer. In other words, an element with five electronic layers will be in the fifth period.

The atomic number is represented by the letter Z and is the number of protons that have their atoms in the nucleus. The atomic number of silver [47] is higher than that of ruthenium [44] because silver has higher number of protons more than ruthenium. Ruthenium and silver are in the same period and they have the same number of atomic orbital but have different atomic numbers.

So the answer is Silver.

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How many significant figures are in the following measurement? 433.8 liters

motikmotik

4 significant figures

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3 years ago

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Your town is having a meeting about whether or not to allow residents to build solar panels on their houses. Many people are aga

julsineya [31]

Putting solar panels on houses is a great idea, for it provides a renewable source of energy and heat, which is the sun. It will help prevent pollution and the mass-use of non-renewable resources, such as fossil fuels, which are used and burned for energy.

Although, having solar panels, there will be some downsides. For example, solar panels can only receive energy during time where there is light from the sun, which is daylight. therefore, the solar panels will not and cannot be able to collect energy from the sun during night time. although, depending on the solar panels, some can store energy, from the sun, that can be used at night time, like as if you're charging a battery with energy from the sun for later use. one big problem is that, solar panels are not cheap and rather quite expensive, which not all homes and families can afford. although, through time, solar panels will get cheaper.

but, all in all, I believe that solar panels give a great contribution to Earth, thus I agree to the use of solar panels.

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4 years ago

What data can be used to make a model of food?

drek231 [11]

Answer: the density of the object / the mass it takes to stand up.

Explanation:

7 0

3 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is $1.3\times 10^2g$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

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3 years ago

To survive and advance, humans have used the natural resources in their environment for at least as long as recorded history.

Otrada [13]

Answer:

water, as there is 0.01% of itis left, mainly from polar caps, potable water is present, if it is not used carefully, then there will be no potable water for us to drink

Explanation:

3 0

4 years ago