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3 years ago

How does the energy of an electron close to the nucleus compare to the energy of electrons farther away from the nucleus?

Chemistry

2 answers:

S_A_V [24]3 years ago

6 0

The electrons closer to the nucleus would have more energy than the electrons farther away from the nucleus.

astra-53 [7]3 years ago

4 0

If the electrons are closer to the nucleus, it will get a lot more energy than if you were further away.

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The reaction C 4 H 8 ( g ) ⟶ 2 C 2 H 4 ( g ) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ / mol. 262 kJ/mol. At 600.0 K,

ludmilkaskok [199]

Answer: $4.3\times 10^{-13}s^{-1}$

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $775.0$ = $?$

$Ea$ = activation energy for the reaction = 262 kJ/mol = 262000J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $775.0K$

Now put all the given values in this formula, we get

$\log (\frac{6.1\times 10^{-8}}{K_2})=\frac{262000}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{775.0K}]$

$\log (\frac{6.1\times 10^{-8}s^}{K_2})=5.150$

$(\frac{6.1\times 10^{-8}}{K_2})=141253.8$

Therefore, the value of the rate constant at 775.0 K is $4.3\times 10^{-13}s^{-1}$

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2 years ago

Which of the following best describes physical science?

Alex17521 [72]

The study of matter and energy best describes physical science. Hence, option B is correct.

<h3>What is physical science?</h3>

Physical science is the study of the inorganic world.

Physics is a branch of science that studies matter and its motion through space and time, along with related concepts such as energy and force. Physics is one of the "fundamental sciences" because of the other natural sciences (like biology, geology etc.)

Thus the study of matter and energy best describes physical science. Hence, option B is correct.

Learn more about the physical science here:

brainly.com/question/12842883

#SPJ1

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2 years ago