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sesenic [268]
3 years ago
8

what volume, in liters, will 6.32 × 10^2 of air occupy if the density of air is 1.29 g/L? Express your answer in scientific nota

tion.
Chemistry
2 answers:
leonid [27]3 years ago
7 0

Explanation:

It is known that density is amount of mass present in per unit volume of the substance.

Mathematically,      Density = \frac{mass}{volume}

It is given that mass is 6.32 \times 10^{2} g and density is 1.29 g/L.

Therefore, calculate the volume by putting the given values into the above formula as follows.

                Density = \frac{mass}{volume}

                  1.29 g/L = \frac{6.32 \times 10^{2} g}{volume}

              volume = 489.92 L

Thus, we can conclude that volume of the air is 489.92 L.

xz_007 [3.2K]3 years ago
3 0

4.90× 10^2 L

I am guessing that the mass of the air is 6.32 × 10^2 <em>g</em>. Then,

Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L

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Answer:

(A) 800 K (B) 2.4 KW

Explanation:

We have given the COP =1.6

The sink temperature T_L=300K

We have to find the source temperature, that is T_H

(A) We know that COP of the heat pump is given by COP=\frac{T_H}{T_H-T_L}

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0.6T_H=480

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(B) We have given the work done =1.5 KW

The rate of heat transfer is given by Q_H=COP\times W=1.6\times 1.5=2.4KW

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