Question

what volume, in liters, will 6.32 × 10^2 of air occupy if the density of air is 1.29 g/L? Express your answer in scientific notation.

Answer 1

Explanation:

It is known that density is amount of mass present in per unit volume of the substance.

Mathematically,      Density = $\frac{mass}{volume}$

It is given that mass is $6.32 \times 10^{2} g$ and density is 1.29 g/L.

Therefore, calculate the volume by putting the given values into the above formula as follows.

                Density = $\frac{mass}{volume}$

                  1.29 g/L = $\frac{6.32 \times 10^{2} g}{volume}$

              volume = 489.92 L

Thus, we can conclude that volume of the air is 489.92 L.

Answer 2

4.90× 10^2 L

I am guessing that the mass of the air is 6.32 × 10^2 g. Then,

Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L