Without constants you would not know which variable affected the
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Molarity after dilution : 0.0058 M
<h3>Further explanation </h3>The number of moles before and after dilution is the same
The dilution formula
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
M₁=0.1 M
V₁=6.11
V₂=105.12
Explanation:
The reaction equation will be as follows.
Hence, the expression for is as follows.
Let us assume that the concentration of both and
is x.
x = 0.01118034
This means that the concentration of is 0.01118034.
Since, we know that the relation between pH and concentration of hydrogen ions is as follows.
pH =
=
= 1.958
Thus, we can conclude that the pH of a 0.500 M solution of arsenic acid is 1.958.