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The number of moles of each product that are formed if 2 moles of Fe2O3 react with 9 moles of CO is 4 moles of Fe and 6 moles of CO2
Explanation
write a balanced chemical reaction
that is FeO3 + 3 CO → 2 Fe + 3CO2
2 moles of Fe2O3 reacted with 3 x2=6 moles of Co to form Fe and CO2 therefore CO was in excess and Fe2O3 was limiting reagent.
use the mole ratio to determine the moles of each product.
that is <em>the mole ratio 0f Fe2O3 : Fe is 1:2 therefore the moles of Fe = </em>2x2=4 moles
<em>the mole ratio of Fe2CO3 : CO2 is 1: 3 therefore the moles of Co2 =</em><em> 2 x3= 6 moles</em>
Answer:
i think quantitative cuz qualitative is like smell and other senses
Explanation:
1 mole ----------------- 6.02 x 10²³ molecules
10.0 moles ----------- ( molecules C2H6O)
molecules = 10.0 x ( 6.02 x 10²³ ) / 1
molecules = 6.02 x 10²⁴ / 1
= <span> 6.02 x 10²⁴ molecules of C2H6O
</span>
Barium peroxide is BaO2.
Hydrogen peroxide is H2O2
This reaction produces hydrogen peroxide from barium peroxide:
BaO2 + H2SO4 ---> BaSO4 + H2O2
So, 1 mol of BaO2 produces 1 mol of H2O2.
Convert 1.50 g of BaO2 to moles:
moles = mass in grams / molar mass
molar mass of BaO2 = 137g/mol + 2*16g/mol = 169 g/mol
moles of BaO2 = 1.50g / 169 g/mol = 0.00888 moles
Then, the same number, 0.00888, will be produced of H2O2.
Now convert 0.00888 moles of H2O2 to mass in grams:
mass in grams = number of moles * molar mass
molar mass of H2O2 = 2 * 1 g/mol + 2 * 16 g/mol = 34 g/mol
mass of H2O2 = 0.00888 moles * 34 g/mol = 0.30192 grams.
Rounded to 3 significant figures = 0.302 grams.
Answer: 0.302 grams