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Vilka [71]
3 years ago
13

During an automobile crash test, the average force exerted by a solid wall on a 1,700 kg car that hits the wall is measured to b

e 170,000 N over a 0.14 s time interval. What was the initial speed of the car (in m/s) prior to the collision, assuming the car is at rest at the end of the time interval
Physics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

14 m/s

Explanation:

Step One:

Given data:

mass of automobile m= 1700kg

Force F= 170,000 N

time t= 0.14s

v= ??

Required

The velocity of the car

Step two:

From the expression given below, we can find the velocity

Ft= mv

make v subject of the formula

v= Ft/m

v= 170000*0.14/1700

v=23800/1700

v=14 m/s

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An object is 39 cm away from a concave mirrors surface along the principles axis. If the mirrors focal length is 9.50 cm, how fa
Tatiana [17]

Answer:

12.6 cm

Explanation:

We can use the mirror equation to find the distance of the image from the mirror:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where here we have

f = 9.50 cm is the focal length

p = 39 cm is the distance of the object from the mirror

Solving the equation for q, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{9.50 cm}-\frac{1}{39 cm}=0.080 cm^{-1}\\q = \frac{1}{0.080 cm}=12.6 cm

5 0
3 years ago
During the time interval from 0.0 to 10.0 s, the position vector of a car on a road is given by x(t) = a + bt + ct2, with a = 17
Juli2301 [7.4K]

The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

<h3>Average velocity of the car</h3>

The average velocity of the car is calculated as follows;

x(t) = a + bt + ct2

v = dx/dt

v(t) = b + 2ct

v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s

v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s

<h3>Average velocity</h3>

V = ¹/₂[v(0) + v(10)]

V = ¹/₂ (-10.1  + 11.9 )

V = 0.9 m/s

Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

3 0
2 years ago
Because of churning rock and ash, the largest volcanic eruptions are sometimes surrounded by
Sonja [21]
Calderas are what sometimes surround it
7 0
3 years ago
A heat pump operates on a Carnot heat pump cycle with a COP of 8.7. It keeps a space at 248C by consum-ing 2.15 kW of power. Det
Marizza181 [45]

Answer:

<em>Heat of the reservoir is 461.38 K or 188.1 °C</em>

<em>The heating load is 18.705 kW</em>

Explanation:

COP = 8.7

working temperature T_{h} = 248 °C = 248 + 273.3 = 521.3 K

work power W = 2.15 kW

reservoir temperature T_{c} = ?

heating load Q = ?

We know that

COP = Q/W

Q = COP x W = 8.7 x 2.15 = <em>18.705 kW</em>

Also,

COP = \frac{T_{h} }{T_{h}- T_{c}  } = \frac{521.3}{521.3- T_{c}  }

8.7 = \frac{521.3}{521.3- T_{c}  }

4535.31 - 8.7T_{c}  = 521.3

4535.31 - 521.3 = 8.7T_{c}  

4014.01 = 8.7T_{c}  

T_{c}  = 4014.01/8.7 = <em>461.38 K</em>

or 461.38 -273.3 = <em>188.1 °C</em>

3 0
3 years ago
Pliss help...
natita [175]

Answer:

I think it is A

Explanation:

Below, what belongs to the organs of the circulatory system in humans is...

<em>a. heart - kidneys - lungs</em>

b. heart-blood vessels - blood

c. heart - kidney - liver

d. heart - lungs

7 0
2 years ago
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