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muminat
3 years ago
9

A design process creating workable systems is called??

Physics
2 answers:
Vesnalui [34]3 years ago
8 0
I believe that it is RAD

azamat3 years ago
6 0
The answer is actually RAD
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In an emergency situation, firemen need to respond as quickly as possible. If a fireman is responding from the second floor, how
rjkz [21]

Answer:

4m/s

Explanation:

May be different considering how long the pole is and how heavy the firefighter is.

8 0
2 years ago
A certain superconducting magnet in the form of a solenoid of length 0.300 m can generate a magnetic field of 8.90 T in its core
Ivan

Answer:

The number of turns in the solenoid is 22366.

Explanation:

The number of turns in the solenoid can be found using the following equation:

B = \mu_{0} I\frac{N}{L}

Where:

B: is the magnetic field = 8.90 T

L: is the solenoid's length = 0.300 m

N: is the number of turns =?

I: is the current = 95 A

μ₀: is the magnetic constant = 4π×10⁻⁷ H/m

By solving equation (1) for N we have:

N = \frac{BL}{\mu_{0} I} = \frac{8.90 T*0.300 m}{4\pi \cdot 10^{-7} H/m*95 A} = 22366 turns

Therefore, the number of turns in the solenoid is 22366.

I hope it helps you!

8 0
3 years ago
_________ is the increase in density of a medium due to wave travel.
Alekssandra [29.7K]

Answer:

<h2>compression</h2>

Explanation:

Such type of the longitudinal waves that causes compression during the travelling through the medium is called as compression. Generally, displacement of the medium takes place in this wave travelling conditions. There are many waves that are considered as longitudinal waves such as sound waves, seismic p-waves and some other. Waves have different types of properties that are changed due to different medium.

5 0
3 years ago
Read 2 more answers
If the distance between two asteroids is halved, the gravitational force they exert on each other will
mamaluj [8]

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_{1} & m_{2}) and the distance between them (r) in the next way:

F=G\frac{m_{1}m_{2}}{r^{2}} (2)

Now if distance between asteroids is halved:

F_{2}=G\frac{m_{1}m_{2}}{(\frac{r}{2})^{2}}

F_{2}=G\frac{m_{1}m_{2}}{\frac{r^{2}}{4}}

F_{2}=G\frac{4m_{1}m_{2}}{r^{2}}=4G\frac{m_{1}m_{2}}{r^{2}}

Note that G\frac{m_{1}m_{2}}{r^{2}} because (1) is F so:

F_{2}=4F

It's four times greater!

3 0
3 years ago
Brandon pushes an object on a ramp as shown in the diagram.
stiks02 [169]

The force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is: B. a frictional force.

<h3>What is a force?</h3>

A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.

<h3>The types of force.</h3>

In Science, there are different types of force and these include the following:

  • Gravitational force
  • Tension force.
  • Electrical force
  • Normal Force.
  • Magnetic force
  • Air resistance force
  • Applied force
  • Frictional force.

<h3>What is a frictional force?</h3>

Friction force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.

In this context, we can infer and logically deduce that the force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is a frictional force.

Read more on frictional force here: brainly.com/question/25253774

#SPJ1

Complete Question:

Brandon pushes an object on a ramp as shown in the diagram.

While Brandon pushes the object and it remains in contact the ramp, which force has the greatest effect on causing it to slow?

A. the applied force

B. a frictional force

C. the force due to gravity

D. a force of air resistance

5 0
1 year ago
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