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Korvikt [17]
3 years ago
11

Lisa's penny bank is 1/10 full. After she adds 440 pennies, it is 3/5 full. How many pennies can Lisa's bank hold?

Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

Step-by-step explanation:

After the 440 pennies are added, the bank is 3/5 full.  It started out 1/10 full, so

3/5 - 1/10 is the amount of space in the bank that the 440 pennies took up, or

1/2.  Use proportions to solve this, with number of pennies on the top and the fraction of the bank that is filled on the bottom:

\frac{440}{\frac{1}{2} }=\frac{x}{1}

where x is the number of pennies (our unknown) that it will take to fill the bank (1).  Cross multiply to get

\frac{1}{2}x=440

so x = 880

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(ii) Rule: To get the next term multiply the previous term by<br> First term =<br> 3
ad-work [718]

Answer:

3×5+2=17 than just do it again 17×5+2=87

Step-by-step explanation:

3×5+2=17, 17×5+2=87

7 0
3 years ago
a physical trainer measures her heart rate and counts that it beats 30 times in 15 seconds. what is the unit rate for her heart
nikitadnepr [17]
The unit rate is 2 beats per second.


3 0
3 years ago
Help plz, these questions are very confusing :/
padilas [110]

Answer:

1.

cos ∅=b/h=24/25

:.b=24

h=25

by using Pythagoras law

h²=p²+b²

25²=p²+24²

p²=25²-24²

p=√7²=7

now

sin ∅=P/h=7/25

tan∅=p/b=7/24

2.cos ∅ is your answer

sec∅-sin∅tan∅

1/cos∅-sin²/cos∅

(1-sin²∅)/cos∅

cos²∅/cos∅

cos∅

3.

tan²∅-sec²x

sin²∅/cos²∅-¹/cos²∅

(sin²∅-1)/cos²∅

8 0
2 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

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6 0
1 year ago
Set up an equation that can be used to solve the problem. Solve the equation and determine the desired value.
Nataly [62]

Answer:  $454.55

Step-by-step explanation:

Tito's weekly salary is always $ 500 per week.

But your weekly commission income depends on the sales you make. Your commissions are 55%.

If we call x the dollar amount of all sales made by Tito in a week, then his income z(x) is given by the following equation:

z (x) = 0.55x + 500

We wish that z (x) = 750.

Then we equate the equation to 750 and solve for the variable x.

0.55x + 500 = 750\\\\0.55x + 500-500 = 750-500\\\\0.55x = 250

\frac{0.55}{0.55}x = \frac{250}{0.55}

x = \$\ 454.55

Total sales made by Tito must be $454.55

7 0
2 years ago
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