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kicyunya [14]
3 years ago
14

What force must be overcome to set an object in motion

Physics
2 answers:
forsale [732]3 years ago
8 0
Newtons Law of motion
HOPE IT HELPS:)
podryga [215]3 years ago
7 0
Friction must be overcome

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Where can you find the neutrons of an atom? in the nucleus with the protons orbiting the nucleus In the nucleus with the electro
cricket20 [7]

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Nuclease is the answer I know

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Do noble gases lose or gain electrons to get a full valence shell?
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They don't lose OR gain electrons as they've already achieved the octet rule and have 8 valence electronsn
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Today chemistry is based on the law ofwhat is the matter ​
melisa1 [442]

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One scientific law that provides the foundation for understanding in chemistry is the law of conservation of matter. It states that in any given system that is closed to the transfer of matter (in and out), the amount of matter in the system stays constant.

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5 0
2 years ago
A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
blsea [12.9K]

Answer:

Negative z-direction

Explanation:

First of all, we need to understand the direction of the magnetic force on the proton. This can be determined by using the right hand rule. So we have:

- index finger: direction of the proton, positive x-direction

- middle finger: direction of magnetic field, positive y-direction

- thumb: direction of the force, positive z-direction

In order to balance this magnetic force, the electric force must act in the opposite direction (negative z direction). Since for a proton (positive charge) the force and the electric field have same direction, it means that the electric field must also be in the negative z direction.

3 0
3 years ago
A positively charged wire with uniform charge density +λ lies along the x-axis and a negatively charged wire with uniform charge
Kisachek [45]

Answer:

\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

Explanation:

The electric field created by an infinitely long wire can be found by Gauss' Law.

\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E2\pi r h = \frac{\lambda h}{\epsilon_0}\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 r} \^r

For the electric field at point (x,y), the superposition of electric fields created by both lines should be calculated. The distance 'r' for the first wire is equal to 'y', and equal to 'x' for the second wire.

\vec{E} = \vec{E}_1 + \vec{E}_2 = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) + \frac{-\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) - \frac{\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

5 0
3 years ago
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