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4 years ago

explain in detail how you would test a gingerbread biscuit solution for the presence of starch, sugar, and protein

1 answer:

5 0

To test a food for starch, you can add a few droplets of iodine to it, if the liquid changes to a blue/black color then starch is present. To test for sugar you can use Benedict's solution, which will also have a color change from blue to yellow/red/orange. Add Biuret Reagent solution to test for protein, the solution will turn a pink or purple color... Note that this may not improve the taste or color of your gingerbread biscuit though :)

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on a recent adventure trip, Anita Break went rock climbing. Anita was able to perform 1370 J of work in 100 seconds. Determine A

Zanzabum

      Power = (energy) / (time)

   =    (1370 joules) / (100 seconds)

   = 13.7 joules/second

   = 13.7 watts .

That's not an awful lot of power, especially for a strenuous activity like
rock-climbing. Shoot ! Even I could probably perform at that level.

Compare 13.7 watts to the light power coming out of a 20-watt night light.

   13.7 watts = 0.018 horsepower. (rounded)

5 0

3 years ago

Help. Please! I really need help. It’s timed, and I’m loosing points.

Archy [21]

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

5 0

3 years ago

A car travels a distance of 100 km. For the first 30 minutes it is driven at a constant speed of 80 km/hr. The motor begins to v

gregori [183]

Explanation:

First, we need to determine the distance traveled by the car in the first 30 minutes, $d_{\frac{1}{2}}$ .

Notice that the unit measurement for speed, in this case, is km/hr. Thus, a unit conversion of from minutes into hours is required before proceeding with the calculation, as shown below

$d_{\frac{1}{2}\text{h}} \ = \ \text{speed} \ \times \ \text{time taken} \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 80 \ \text{km h}^{-1} \ \times \ \left(\displaystyle\frac{30}{60} \ \text{h}\right) \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 80 \ \text{km h}^{-1} \ \times \ 0.5 \ \text{h} \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 40 \ \text{km}$

Now, it is known that the car traveled 40 km for the first 30 minutes. Hence, the remaining distance, $d_{\text{remain}}$ , in which the driver reduces the speed to 40km/hr is

$d_{\text{remain}} \ = \ 100 \ \text{km} \ - \ 40 \ \text{km} \\ \\ \\ d_{\text{remain}} \ = \ 60 \ \text{km}$ .

Subsequently, we would also like to know the time taken for the car to reach its destination, denoted by $t_{\text{remian}}$ .

$t_{\text{remain}} \ = \ \displaystyle\frac{\text{distance}}{\text{speed}} \\ \\ \\ t_{\text{remain}} \ = \ \displaystyle\frac{60 \ \text{km}}{40 \ \text{km hr}^{-1}} \\ \\ \\ t_{\text{remain}} \ = \ 1.5 \ \text{hours}$ .

Finally, with all the required values at hand, the average speed of the car for the entire trip is calculated as the ratio of the change in distance over the change in time.

$\text{speed} \ = \ \displaystyle\frac{\Delta d}{\Delta t} \\ \\ \\ \text{speed} \ = \ \displaystyle\frac{100 \ \text{km}}{(0.5 \ \text{hr} \ + \ 1.5 \ \text{hr})} \\ \\ \\ \text{speed} \ = \ \displaystyle\frac{100 \ \text{km}}{2 \ \text{hr}} \\ \\ \\ \text{speed} \ = \ 50 \ \text{km hr}^{-1}$

Therefore, the average speed of the car is 50 km/hr.

8 0

3 years ago

If you had an unlimited amount of mass to hang, what would be the range of possible accelerations for the system?

LenaWriter [7]

Answer:

The entire cart/hanging mass system follows the same law, ΣF = ma. This means that plotting force vs. acceleration yields a linear relationship (of the form y = mx).

3 0

3 years ago

Deadpool is doing a superhero landing from a 21 meter tall building what would his velocity be right before he hits the ground?

Morgarella [4.7K]

Answer:

I think he would be dead poggers

Explanation:

4 0

3 years ago