The solid aluminum shaft has a diameter of 50 mm. Determine the absolute maximum shear stress in the shaft and sketch the shear-
1 answer:
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Answer:
a) 42.422 KN
b) 44.356 KN
Explanation:
Given data :
Diameter = 20 mm
yield strength = 350 MN/m^2
Torque ( T ) = 100 N.m
Bending moment = 150 N.m
<u>Determine the value of the applied axial tensile force when yielding of rod occurs </u>
first we will calculate the shear stress and normal stress
shear stress ( г ) = Tr / J = [( 100 * 10^3) * 10 ] / * ( 20)^4
= 63.662 MPa
Normal stress( Гb + Гa ) = MY/ I + P/A
= [( 150 * 10^3) * 10 ] / * ( 20)^4 + 4P /
= 190.9859 + 4P / MPa
<u>a) Using MSS theory </u>
value of axial force = 42.422 KN
solution attached below
<u>b) Using MDE theory </u>
value of axial force = 44.356 KN
solution attached below
Answer:
hello your question is incomplete attached below is the complete question and the detailed solution
Answer: A) 5.17 GHz
B) 1.01 GHz
Explanation:
Assuming the transistor is biased and considering the two conditions as given in A and B attached below is a detailed solution to the given problem
Answer:
The air heats up when being compressed and transefers heat to the barrel.
Explanation:
When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.
In an adiabatic transformation:
For air k = 1.4
SO
SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.
After it was compressed the hot air will exchange heat with the barrel heating it up.