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Vaselesa [24]
3 years ago
5

If you go to the beach and get a cup of water out of the ocean, does the water in the cup have the same average kinetic energy a

s the ocean? the same thermal energy
Physics
1 answer:
DiKsa [7]3 years ago
3 0
Yes, the water in the cup have the same average kinetic energy as the ocean, because I focus on the word 'average'. However the cup of water have less INTERNAL energy than the ocean.
hope it helps☺☺
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A bird uses 10 N of force to pull a worm out of the ground a distance of 3 inches. How much work did the bird do?
pochemuha

Answer:

The work done by the bird is 0.762 J

Explanation:

Given;

force applied by the bird, f = 10 N

distance the bird moved the worm, d = 3 inches = 0.0762 m

The work done by the bird is given by;

W = F x d

where;

W is the work done by the bird

d is the distance the bird moved the load

Substitute the given values and estimate the work done by the bird;

W = 10 x 0.0762

W = 0.762 J

Therefore, the work done by the bird is 0.762 J

6 0
3 years ago
Near the equator, the patterns of convection currents are called ________.
tatyana61 [14]
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8 0
3 years ago
The traffic on the freeway is moving at a constant speed of 24 m/sm/s. What distance does the traffic travel while the car is mo
ExtremeBDS [4]

Incomplete question as there is so much information is missing.The complete question is here

A car sits on an entrance ramp to a freeway, waiting for a break in the traffic. Then the driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 24 m/s (54 mi/h) when it reaches the end of the 120-m-long ramp. The traffic on the freeway is moving at a constant speed of 24 m/s. What distance does the traffic travel while the car is moving the length of the ramp?

Answer:

Distance traveled=240 m

Explanation:

Given data

Initial velocity of car v₀=0 m/s

Final velocity of car vf=24 m/s

Distance traveled by car S=120 m

To find

Distance does the traffic travel

Solution

To find the distance first we need to find time, for time first we need acceleration

So

(V_{f})^{2}=(V_{o})^{2}+2aS\\  So\\a=\frac{(V_{f})^{2}-(V_{o})^{2} }{2S}\\ a=\frac{(24m/s)^{2}-(0m/s)^{2} }{2(120)}\\a=2.4 m/s^{2}

As we find acceleration.Now we need to find time

So

V_{f}=V_{i}+at\\t=\frac{V_{f}-V_{i}}{a}\\t=\frac{(24m/s)-(0m/s)}{(2.4m/s^{2} )}\\t=10s

Now for distance

So

Distance=velocity*time\\Distance=(24m/s)*(10s)\\Distance=240m

7 0
3 years ago
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