Question

A transformer on a 220 V line has 55 loops on the primary and 440 loops on the secondary and draws a 4.00 a current. Assuming no losses:
(A) what is the voltage from the secondary?
(B) what is the currency from the secondary?
(C) what is the power output?

Answer 1

For transfomers (robots in disguise), there are equations to help us solve these problems.

Here are the equations you need:

$\frac{V_{p}}{V_{s}}= \frac{n_{p}}{n_{s}}$

$V_{p}$ is our V primary, $v_{s}$ is our V secondary, $n_{p}$ is our number of loops on our primary and $n_{s}$ is number of loops in our secondary.

Plugging our known values in, we can solve for the secondary voltage.

$\frac{220}{V_{s}}= \frac{55}{440}$
$V_{s} = 1760V$

For current, we have another equation:

$V_{p}I_{p}=V_{s}I_{s}$

Just like before, we can plug in our known values:

$(220V)(4A)=(1760V)I_{s}$
$I_{s}= 0.5A$

Since we are told there are no losses, the input power must equal output power.

(0.5A)(1760V)=(220V)(4A) = 880W