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3 years ago

Which of the following types of electromagnetic radiation has the longest wavelength?

Physics

2 answers:

ale4655 [162]3 years ago

8 0

Answer:

radio waves

Explanation:

mash [69]3 years ago

6 0

Answer:

Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

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A 25 kg child is riding on a swing. If the child travels 8.9 m/s at the bottom of their swing, how high into the air is the chil

Setler [38]

Answer:

h = 4.04 m

Explanation:

Given that,

Mass of a child, m = 25 kg

The speed of the child at the bottom of the swing is 8.9 m/s

We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

$mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}$

Put all the values,

$h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m$

So, the child is able to go at a height of 4.04 m.

7 0

3 years ago

If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle

soldi70 [24.7K]

Answer:

The angle that the wave would be $\theta = sin ^{-1}\frac{2 \lambda}{D}$

Explanation:

From the question we are told that the opening to the harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the on at angle greater than the diffraction first minimum would be slightly affected

The minimum is as a result of destructive interference

And for single-slit this is mathematically represented as

$D sin \ \theta =m \lambda$

where D is the slit with

$\theta$ is the angle relative to the original direction of the wave

m is the order of the minimum j

$\lambda$ is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

And the both is safe at the angle equal to the second minimum then

The the angle is evaluated as

$\theta = sin ^{-1}[\frac{m\lambda}{D} ]$

Since for second minimum m= 2

The equation becomes

$\theta = \frac{2 \lambda}{D}$

3 0

3 years ago

A 3,000 kg truck moving at +10 m/s hits a 1,000 kg parked car which moves off at +15 m/s What is the velocity of

Rina8888 [55]

Answer:

v₃ = 5 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

P = m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

We must also clarify that the momentum is preserved i.e. it is equal before the collision and after the collision

Pbeforecollision = Paftercollision

(m₁*v₁) + (m₂*v₂) = (m₁*v₃) + (m₂*v₄)

where:

m₁ = mass of the truck = 3000 [kg]

v₁ = velocity of the truck = 10 [m/s]

m₂ = mass of the car = 1000 [kg]

v₂ = velocity of the car before the collision = 0 (the car is parked)

v₃ = velocity of the truck after the collision [m/s]

v₄ = velocity of the car after the collision = 15 [m/s]

(3000*10) + (1000*0) = (3000*v₃) + (1000*15)

30000 = 3000*v₃ + 15000

3000*v₃ = 30000 - 15000

3000*v₃ = 15000

v₃ = 5 [m/s]

7 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Joules could be used to measure

lyudmila [28]

All of the above, work is a measurement of energy transfer, in Joules.

Potential energy = Joules

Kinetic energy = Joules

The key thing here is that anything having to do with just energy or energy transfer is measured in joules.

4 0

3 years ago

Your roommate drops your wallet down to you from the third-floor window of your apartment, which is 11.5 m from the ground. What

Aneli [31]

Answer:

15 m/s

Explanation:

Using the law of conservation of energy, potential energy equals kinetic energy hence

$mgh=0.5mv^{2}$

Therefore

$v=\sqrt{2gh}$

where g is the acceleration due to gravity, m is the mass of the object, h is the height and v is the speed of the wallet

Taking g as 9.81 then

$v=\sqrt{2\times 9.8\times 11.5}=15.02098532 m/s\approx 15 m/s$

6 0

3 years ago