Answer:
B. A plant gets the things it needs to survive from its environment.
Hello!
The general chemical reaction for the combustion of a fossil fuel is the following one:
C(s) + O₂(g) → CO₂(g)
Now, we use the following conversion factor to go from kilograms of CO₂ to kilograms of O₂, using the molar masses of each compound and the reaction coefficients:
![5*10^{12} kg CO_2* \frac{1000g}{1 kg}* \frac{1 molCO_2}{44,01 g CO_2}* \frac{1 mol O_2}{1 mol CO_2}* \frac{32gO_2}{1molO_2}* \frac{1kg}{1000g} \\ \\ = 3,64*10^{12}kgO_2](https://tex.z-dn.net/?f=5%2A10%5E%7B12%7D%20kg%20CO_2%2A%20%5Cfrac%7B1000g%7D%7B1%20kg%7D%2A%20%5Cfrac%7B1%20molCO_2%7D%7B44%2C01%20g%20CO_2%7D%2A%20%5Cfrac%7B1%20mol%20O_2%7D%7B1%20mol%20CO_2%7D%2A%20%5Cfrac%7B32gO_2%7D%7B1molO_2%7D%2A%20%5Cfrac%7B1kg%7D%7B1000g%7D%20%5C%5C%20%20%5C%5C%20%3D%203%2C64%2A10%5E%7B12%7DkgO_2%20%20%20%20)
So, for producing 5*10¹² kg of CO₂,
3,64*10¹² kg of O₂ are required.
Have a nice day!
Hello!
The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is
0,725 atmTo solve this problem we first need to set up the data in the appropriate units to input it in the
Ideal Gas Law.
a) 16 g of Oxygen gas to moles of oxygen gas:
![16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2](https://tex.z-dn.net/?f=16gO_2%2A%20%5Cfrac%7B1%20mol%20O_2%7D%7B32gO_2%7D%3D0%2C5%20mol%20O_2)
b) 45 °C to K
![K=$^{\circ}$C + 273,15 = 45 $^{\circ}$C + 273.15=318,15 K](https://tex.z-dn.net/?f=K%3D%24%5E%7B%5Ccirc%7D%24C%20%2B%20273%2C15%20%3D%2045%20%24%5E%7B%5Ccirc%7D%24C%20%2B%20273.15%3D318%2C15%20K%20)
Now, we clear the Ideal Gas Equation for P, and solve it:
![P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm](https://tex.z-dn.net/?f=P%2AV%3Dn%2AR%2AT%20%5C%5C%20%5C%5C%20P%3D%20%5Cfrac%7Bn%2AR%2AT%7D%7BV%7D%3D%20%5Cfrac%7B%280%2C5mol%29%2A%280%2C082%20%5Cfrac%7BL%2Aatm%7D%7Bmol%2AK%7D%29%2A%20%28318%2C15%20K%29%7D%7B18%20L%7D%3D%200%2C725%20atm%20)
Have a nice day!
Answer: ![CH_3OH(l)\rightarrow CH_3OH(aq)](https://tex.z-dn.net/?f=CH_3OH%28l%29%5Crightarrow%20CH_3OH%28aq%29)
Explanation:
According to the concept of “Like dissolves like”, the polar solutes dissolve in polar solvents, and non-polar solutes dissolve in non-polar solvents.
Covalent compounds which are formed by sharing of electrons between non metals, when dissolved in water, forms hydrogen bonding with water if they contain a electronegative atom along with hydrogen. Example: methanol ![(CH_3OH)](https://tex.z-dn.net/?f=%28CH_3OH%29)
Ionic compounds which are made up of cations and anions, when dissolved in water, dissociate into ions. Example: ![NaCl](https://tex.z-dn.net/?f=NaCl)
Thus equation which best represents methanol being dissolved in water is:
![CH_3OH(l)\rightarrow CH_3OH(aq)](https://tex.z-dn.net/?f=CH_3OH%28l%29%5Crightarrow%20CH_3OH%28aq%29)
Answer:
Solvents are substances in which solutes dissolves while solutes are substances that dissolve in solvents and solutions result from mixing solvents and solutes.
Explanation:
- A solvent is a substance such as water that dissolves a solute.
- A solute is a substance that dissolves in a solvent. For example, when sodium chloride dissolves in water, sodium chloride is the solute and water is the solvent.
- A solution, on the other hand, results from combining a solute and a solvent. Therefore, a mixture of water and sodium chloride forms the solution.