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kondaur [170]
3 years ago
14

What is likely to happen if we can't control our experiment properly? A. Our hypothesis will have to be changed. B. We will need

to do other experiments and collect more data. C. Our hypothesis will be well-supported by the data we collect. D. We will have to make more inferences instead of collecting data.
Chemistry
2 answers:
REY [17]3 years ago
4 0
The answer to your question
is b 
katovenus [111]3 years ago
4 0

Answer:

The answer is <u><em>letter D</em></u>

Explanation:

It is the only one that makes sense, i dont have a proper explanation unfortunately, its just guts. sorry, this probably wont help, but i tried agaga

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Plss help me asap!!!!​
Tanzania [10]

Answer:

Based on the evidence, the layers, of which the fossils were discovered, the climate was a beach before becoming a forest.

Explanation:

8 0
2 years ago
A 1.00 liter solution contains 0.42 moles nitrous acid and 0.32 moles sodium nitrite .
xeze [42]

Answer:

E. The ratio of [HNO2] / [NO2-] will increase

D. The pH will decrease.

Explanation:

Nitrous acid ( HNO₂ ) is a weak acid and NaNO₂ is its salt . The mixture makes a buffer solution .

pH = pka + log [ salt] / [ Acid ]

= 3.4 + log .32 / .42

= 3.4 - .118

= 3.282 .

Now .16 moles of nitric acid is added which will react with salt to form acid

HNO₃ + NaNO₂ = HNO₂ + NaNO₃

concentration of nitrous acid will be increased and concentration of sodium nitrite ( salt will decrease )

concentration of nitrous acid = .42 + .16 = .58 M

concentration of salt = .32 - .16 = .16 M

ratio of [HNO₂ ] / NO₂⁻]

= .42 / .32 = 1.3125

ratio of [HNO₂ ] / NO₂⁻] after reaction

= .42 + .16 / .32 - .16

= 58 / 16

= 3.625 .

ratio will increase.

Option E is the answer .

pH after reaction

= 3.4 + log .16 / .58

= 2.84

pH will decrease.

4 0
3 years ago
Water (2850 g ) is heated until it just begins to boil. If the water absorbs 5.53×105 j of heat in the process, what was the ini
NARA [144]

Answer is 54 °C.

<em>Explanation;</em>

We can simply use heat equation

Q = mcΔT  

 Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

Let's assume that the initial temperature is T.

Q = 5.53 × 10⁵ J

m = 2850 g

c = 4.186 J/g °C

ΔT = (100 - T)  °C     <em>Since the water is boiling, the final temperature is 100 °C.</em>

By applying the equation,

5.53 × 10⁵ J  = 2850 g  x 4.186 J/g °C  x (100 - T)  °C

(100 - T)  °C = 5.53 × 10⁵ J  / (2850 g  x 4.186 J/g °C  )

(100 - T)  °C = 46.35 °C

         T        = 100 - 46.35 C = 53.65 °C

                   ≈ 54 °C

7 0
4 years ago
A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 0.300 atm at 20.0°C. The round part of the tan
frez [133]

Answer:

Part A m = 97.37 Kg

Part B H = 4.59 meters

Explanation:

Part A

Pressure is equal to force per unit area

P = \frac{F}{A}

Here force is equal to the weight of the piston

Thus

P = \frac{m*g}{A}

On rearranging the equation, we get -

m = \frac{PA}{g} \\m = \frac{P\pi r^2}{g}

Substituting the given values we get

m = \frac{0.3*1.013*10^5*0.1^2}{9.8} \\m = 97.37

Part B

We know that

V = \pi r^2h\\

On substituting the given values we get -

pV = nRT\\V = \frac{nRT}{p}

V = \frac{1.8*8.314*293}{0.3039*10^5} \\V = 0.1442 m^3

Height

= \frac{V}{\pi r^2} \\= \frac{0.1442}{\pi 0.1^2} \\= 4.59

4 0
3 years ago
How many spatial orientations are available for the p sublevel
Sonja [21]

4 to 5 you are welcome

3 0
3 years ago
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