The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
<h3>What is the Grignard reagent?</h3>
The Grignard reagent is a compound that contains alkyl magnesium halide.
a) The student will be unsuccessful to prepare a Grignard reagent from 4-bromocyclohexanol because of the -OH group that reacts with the Grignard reagent when formed.
b) The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
c) The compound (2S, 3R)- 2,3-Dibromobutane has a specific rotation, [a]D, 0⁰ because it is a meso compound.
d) This is because, the tertiary alkyl halide is more prone to elimination reaction giving the alkene.
e) This is because, the reaction may be occurring by an SN1 mechanism and the rate determining step is the formation of the carbocation.
Learn more about substitution reaction:brainly.com/question/16811879
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Explanation :
As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.
He placed the elements with similar nature in the same group.
According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.
However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.
As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127 and tellurium isotopes are tellurium-128 and tellurium-130.
Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.
Answer:
57.6ml
Explanation:
Using dilution formula
C1V1 = C2V2
C1 = 2.903 M, V1 = ? , C2 = 0.3344 M , V2 = 500ml
2.903 × V1 = 0.3344 × 500
V1 =( 0.3344 × 500)/ 2.903
= 57.5956
≈ 57.6ml
