The direction of the buoyant force on an object placed in fluid is

A 70 kilogram hockey player skating east on an ice rink is hit by a 0.1 kilogram hockey puck moving toward the west. The puck ex

guajiro [1.7K]

Given:

70 Kilogram hockey

Hit by 0.1 kilogram

50 Newton

Description:

So in this case this bacially means that one object is experiencing a force then another object. So the answer to the question will be 50N.

Answer: 50N (3rd Law)

Hope this helps.

4 0

3 years ago

An instructor gives a demonstration in which he makes a standing wave on a long thin slinky. The slinky is 6.0 meters long. If y

Naily [24]

The characteristics of standing waves allows to find the result for the speed of the wave is:

The speed wave is: v = 10 m / s

The wave is a way of transmitting energy without mass displacement, , in the attachment we can see a diagram of the standing wave.

Each cycle corresponds to half a wavelength, they indicate that the frequency is 2.50 Hz and there are three cycles, so the wavelength is:

L = $n \frac{\lambda}{2}$

λ = 2L/n

λ = 2 6 /3

λ = 4 m

Wave speed is related to wavelength and frequency

v = λ f

v = 4 2.5

v = 10 m / s

In conclusion, using the characteristics of standing waves we can find the result for the speed of the wave is:

The wave speed is: v = 10 m / s

Learn more here: brainly.com/question/12536719

8 0

3 years ago

A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm

Mashutka [201]

Answer:

$a = 0.53 m/s^2$

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

$\omega = 2\pi f$

$\omega = 2\pi ( \frac{20}{60})$

$\omega = 2.10 rad/s$

so final tangential speed is given as

$v = r\omega$

$v = 1.71 (2.10) = 3.58 m/s$

now average acceleration of the girl is given as

$a = \frac{v_f - v_i}{\Delta t}$

$a = \frac{3.58 - 0}{6.73}$

$a = 0.53 m/s^2$

8 0

3 years ago

What force is necessary to accelerate a 2500 kg care from rest to 20 m/s over 10 seconds?

EleoNora [17]

Force = mass x acceleration
force = 2500kg x (20m/s / 10m/s)
force = 2500kg x 2m/s^2
force = 5000kg m/s^2 = 5kN

i hope this is right (^^)

4 0

2 years ago

Help please physics !!

malfutka [58]

Answer:

Option A. 1 bar = 1 atm

Explanation:

Pressure has various units of measurement. Each unit of measurement can be converted to other units of measurement. For example:

1 atm = 1 bar

1 atm = 760 mmHg

1 atm = 760 torr

1 atm = 1×10⁵ N/m²

1 atm = 1×10⁵ Pa

With the above conversion scale we can convert from one unit to the other.

Considering the question given above, it is evident from the coversion scale illustrated above that only option A is correct.

Thus,

1 bar = 1 atm

5 0

2 years ago