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Paul [167]
3 years ago
5

Calculate the mass (in grams) of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assumi

ng the standard is known to have a hardness of 75.0 ppm (hardness due to CaCO3).
Chemistry
1 answer:
horrorfan [7]3 years ago
7 0
1 part per million is the same as 

<span>1 mcg/mL (mcg = 1 micro gram = 1 * 10^-6 grams). </span>
<span>125 ppm = 125 mcg/mL </span>

<span>125 mcg/ml * [1 gram / 1 * 10^6 mgrm] = 1.25 * 10^-4 grams </span>

<span>The density of hard water is 1.000 grams / mL </span>

<span>50 mL of water contains 1.25 * 10^-4 grams. </span>

<span>given mass = 1.25 * 10^-4 </span>
<span>Molar mass = 100.0 grams / mole </span>
<span>n = ????? </span>

<span>n = 1.25 * 10^-4/100 = 1.25 * 10^-6 moles. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>
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