A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.320 m2. at
1 answer:
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Answer:
frequency = 1475.45 Hz
Explanation:
given data
frequency f1 = 1215 Hz,
frequency f2 = 1265 Hz
police car moving vp = 25.0 m/s
solution
speed of sound u = 343 m / s
speed of the other car = v
when the police car is stationary
the frequency the other car receives is
f2 = f1 × ................1
and
the frequency the police car receives is
f2 = f1 × ..................2
now from equation 1 and 2
v = 4.77 m/s
and
frequency the other car receives is
f2 = f1 × ......................3
and
the frequency the police car receives is
f2 = f1 × .......................4
now we get
f2 = f1 ×
f2 =
f2 = 1475.45 Hz
Answer:
The approximate combined sound intensity is
Explanation:
The decibel scale intensity for busy traffic is 80 dB. so intensity will be
, therefore
In the same way for the loud conversation having a decibel intensity of 70 dB.
, therefore
Finally we add both of them , is the approximate combined sound intensity.