Answer:

Explanation:
We are given the compound: Cs₃PO₄
According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.
Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.


3 moles of cesium phosphate contains <u>9 moles of cesium.</u>
Amide is produced when a 2° amine and an acid chloride combine.
Acid chloride: What is it?
- The chemical name for acid chloride is RCOCl, where "R" stands for a side chain. They are reactive derivatives of carboxylic acids. In organic chemistry, an acyl group and a chlorine atom form an organic molecule known as an acyl chloride (also known as acid chloride).
- A functional group identified by the RCO molecular formula is called an acyl group. Since acyl chlorides are often hazardous, handling them requires extra care.
- They have the potential to produce HCl and organic compounds when they interact with water on the surface of the eye, irritating the eye. Anhydrous acid salts are neutral because it lacks an H+ donor.
Learn more about acid chloride here:
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Na+ + e --> Na
2Cl- --> Cl2 -2e-
Answer: 195.3 K
Explanation: Use Charles Law to get T2
Charles Law V1 / T1 = V2 / T2
Derive the equation to find T2
T2 = V2T1 / V1
Convert temperature into K
T1 = 20.0 °C + 273 = 293 K
Substitute the values:
4.00 L x 293 K / 6.00 L = 195. 3 K
Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms