The intermolecular forces, such as hydrogen bonds or van der Waals attractions, which draw one molecule to its neighbors, govern a substance's physical properties. Due to the relatively weak intermolecular forces of attraction, molecular substances typically take the form of gases, liquids, or low melting point solids.
<h3>How do the intermolecular forces affect physical properties?</h3>
The forces that bind two molecules together are known as intermolecular forces. Intermolecular forces have an impact on physical properties. Strong and weak forces both exist; the stronger the force, the more energy is needed to separate the molecules from one another. As intermolecular forces increase melting, boiling, and freezing points rise.
The following intermolecular forces are listed in order of strength:
- Van der Waals dispersion forces
- Van der Waals dipole-dipole interactions
- Hydrogen bonding
- Ionic bonds
It would take very little energy to separate two molecules if they are connected by van der Waals dispersion forces. On the other hand, it requires a lot more energy to separate two molecules that are joined together by ionic bonds.
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Answer:
c) non polar Covalent
Explanation:
this is a molecule formed by atoms of the same element . they both have similar electronegativities and thus cancel out . This makes it a perfect Covalent molecule . The fact that it's a symmetrical molecule makes it non polar. a symmetrical molecule is a molecule formed by the overlap of orbitals of two atoms of the same element ( that is to say , there's no dipole )
Answer:
No.
Explanation:
If the temperature changes a substance from it's original form, going from solid to liquid, then the temperature required to change it from a liquid to a solid are the opposite. For example, Ice is Water (H2O) in it's solid form. In order to freeze water into ice, the temperature must be very low. In order to melt the ice back into water, the temperature must be higher than the freezing point, but not too high or it will boil, making it a gaseous substance instead.
The rate of the forward an reverse reaction are equal
