Answer: D. Series circuits are simpler than parallel circuits.
Explanation:
In series circuit, all the components are connected in single path of current flow.
If one part of the circuit breaks, complete circuit would break and all the other parts also would not operate.
The voltage is not same everywhere. It is different across each component.
In series circuit, net resistance is more as resistance of all the components connected in series are added up.
So, the only advantage of a series circuit is that is simpler than the parallel circuits. Thus, the correct option is D.
The Balanced Chemical Equation is as follow;
4 KO₂ + 2 CO₂ → 2 K₂CO₃ + 3 O₂
First find out the Limiting Reagent,
According to equation,
284 g (4 moles) KO₂ reacted with = 44.8 L (2 moles) of CO₂
So,
27.9 g of KO₂ will react with = X L of CO₂
Solving for X,
X = (44.8 L × 27.9 g) ÷ 284 g
X = 4.40 L of CO₂
Hence, to consume 27.9 g of KO₂ only 4.40 L CO₂ is required, while, we are provided with 29 L of CO₂, it means CO₂ is in excess and KO₂ is is limited amount, Therefore, KO₂ will control the yield of K₂CO₃. So,
According to eq.
284 g (4 moles) KO₂ formed = 138.2 g of K₂CO₃
So,
27.9 g of KO₂ will form = X g of K₂CO₃
Solving for X,
X = (138.2 g × 27.9 g) ÷ 284 g
X = 13.57 g of K₂CO₃
So, 13.57 g of K₂CO₃ formed is the theoretical yield.
%age Yield = 13.57 / 21.8 × 100
%age Yield = 62.24 %
Answer:
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
Explanation:
![Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%20%28aq%29%20%2B%203%20e%5E-%5Crightarrow%20Fe%20%28s%29%20%2CE%5Eo%20%3D%20-0.036%20V)
![Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V](https://tex.z-dn.net/?f=Mg%5E%7B2%2B%7D%28aq%29%20%2B%202%20e%5E-%20%5Crightarrow%20Mg%20%28s%29%2CE%5Eo%20%3D%20-2.37%20V)
The substance having highest positive reduction
potential will always get reduced and will undergo reduction reaction.
Reduction : cathode
..[1]
Oxidation: anode
..[2]
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the
of the reaction, we use the equation:
![E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3DE%5Eo_%7Bred%2Ccathode%7D-E%5Eo_%7Bred%2Canode%7D)
![E^o_{cell}=-0.036V-(-2.37 V)=2.334 V](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3D-0.036V-%28-2.37%20V%29%3D2.334%20V)
The overall reaction will be:
2 × [1] + 3 × [2] :
![2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-](https://tex.z-dn.net/?f=2Fe%5E%7B3%2B%7D%20%28aq%29%20%2B%203Mg%28s%29%2B6e%5E-%5Crightarrow%202Fe%20%28s%29%2B3Mg%5E%7B2%2B%7D%28aq%29%2B6e%5E-)
Electrons on both sides will get cancelled :
![2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)](https://tex.z-dn.net/?f=2Fe%5E%7B3%2B%7D%20%28aq%29%20%2B%203Mg%28s%29%5Crightarrow%202Fe%20%28s%29%2B3Mg%5E%7B2%2B%7D%28aq%29)
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
Answer:
A
Explanation:
It is correct please I hope it helps! :)
The condensed structure of given compounds are shown in the below image.
<h3>What is functional group?</h3>
Functional group is the specific group which is present in an organic compound gives information about the properties of that compound.
- In 1,2-propanediol compound hydroxyl functional group is present on the 1st and 2nd position.
- In Ethyl methyl ether, ether functional group is present.
- In Dichloromethane, two atoms of chlorine groups are present.
Hence, structure of the given compounds are shown in the below image.
To know more about functional group, visit the below link:
brainly.com/question/6028840
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