Answer:
0.153 moles of hydrogen.
B) Multiply 10 grams of Zn x (1 mol Zn/65.39 g)
Explanation:
Given data:
Mass of zinc = 10 g
Moles of hydrogen = ?
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of zinc:
Number of moles of zinc = mass/ molar mass
Number of moles of zinc = 10 g/ 65.4 g/mol
Number of moles of zinc = 0.153 mol
Now we will multiply the moles of Zn with hydrogen:
Zn : H₂
1 : 1
0.153 : 0.153
<h3>
Answer:</h3>
1.5 × 10²³ atoms Mn
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.25 mol Mn
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.5055 × 10²³ atoms Mn ≈ 1.5 × 10²³ atoms Mn
MY answer would be C knowing what your income is
sorry if im wrong if i am i guess it would be D
<span>which term describes as a flat expanse of ocean floor </span>guyots
Answer:- 8.97 atm.
Solution:- Moles of each gas, volume of the vessel and temperature are given. So, we could easily use the partial pressure of each gas using ideal gas law equation.
PV = nRT
P is the pressure, V is the volume, n is the moles of the gas, R is universal gas constant and T is kelvin temperature.
The equation is rearranged for the pressure as:

To calculate the partial pressure of fluorine we will use its moles.
n = 2.0 mol
V = 5.0 L
T = 273 K
R = 0.0821
P = ?
Let's plug in the values and calculate the partial pressure of fluorine.

P = 8.97 atm
So, the partial pressure of fluorine gas is 8.97 atm.