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AleksandrR [38]
4 years ago
13

A partially dipped stick seems to be bent why

Physics
2 answers:
lidiya [134]4 years ago
7 0

Answer:

refraction

Explanation:

vfiekz [6]4 years ago
6 0
Because it wants to
You might be interested in
An accelerating voltage of 2.47 x 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horiz
Dmitry [639]

Answer:

6.3445×10⁻¹⁶ m

Explanation:

E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s

Deflection by Earth's Gravity

\Delta =\frac {gt^2}{2}

Now, Time = Distance/Velocity

\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m

3 0
3 years ago
Which sizes influence the adhesive and rolling friction?
julsineya [31]

juju on that beat

Explanation:

4 0
3 years ago
a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car
Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 282 kg is the mass of the bumper car

u_1 = 3.50 m/s is the initial velocity of the bumper car (we take the right as positive direction)

v_1 = 0.800 m/s is the final velocity of the bumper car

m_2 = 155 kg is the mass of the second bumper car

u_2 = -1.88 m/s is the initial velocity of the second car (moving to the left)

v_2 is the final velocity of the second car

Solving for v_2,

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s (to the right)

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
How do we find the average force in physics?​
svlad2 [7]
Force is equal to mass multiplied by acceleration. Hope this helps!
8 0
3 years ago
Read 2 more answers
(10%) Problem 2: The frequency range for AM radio is 540 to 1600 kHz. The frequency range for FM radio is 88.0 to 108 MHz.
Dominik [7]

188m - 556m is the wavelength range for AM radio.

2.77 - 3.40m is the wavelength range for FM radio.

1) For AM radio

f(max) = 1600 × 10³ Hz

f(min) = 540 ×10³Hz

c = fλ

λ = c/f where,

c = speed of light

f = frequency

λ= wavelength

So,

λ(min) = 3 × 10^{8} / 1600 × 10³ = 188 m

λ(max) = 3 × 10⁸/540 ×10³ = 556 m

So wavelength range of AM radio is 188 m - 556m

2) For FM radio

f(max) = 108 × 10⁶ Hz

f(min) = 88 × 10⁶ Hz

λ(min)  = 3 × 10⁸ / 108 × 10⁶ = 2.77 m

λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m

So wavelength range of FM radio is 2.77m - 3.40m

Learn more about frequency here brainly.com/question/10728818

#SPJ1

3 0
2 years ago
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