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Vaselesa [24]
2 years ago
13

Base your answer(s) to the following question(s) on the information and diagram

Physics
1 answer:
klio [65]2 years ago
8 0

Done I don't know answer of this question or this photo is the answer can you tell me

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What feature of a chemical equation represents the law of conservation of matter?
Goryan [66]
Answer is: balanced equation.
<span>Law of conservation of matter claims that in a</span>ny system that is closed to the transfer of matter, the amount of matter in the system stays constant. 
Balanced equation states that <span>same number and type of atoms after the chemical reaction must present as before the chemical change.</span>
7 0
3 years ago
Read 2 more answers
A raft is made of 12 logs lashed together. Each is 45 cm in diameter and has a length of 6.5 m. How many people can the raft hol
tatyana61 [14]

Answer:

324 people

Explanation:

radius r = diameter / 2 = 45cm /2 = 22.5 cm or 0.225 m

We can calculate the total volume of the log by computing the volume of each cylindrical log:

V = \pi r^2 L = \pi 0.225^2 * 6.5 = 4.6 m^3

So the total volume of all 12 logs is

12 * 4.6 = 55.135 m^3

The weight that the raft can support, is the buoyancy force subtracted by its own weight.

The buoyancy force is basically the weight of the water is displaced, which is water density times volume. The log weight is also log density times its volume

F = F_b - F_w = g\rho_wV - g\rho_rV = gV(\rho_w - \rho_r)

where \rho_w = 1000kg/m^3,\rho_r are the density of water and raft, respectively. But since we have the specific gravity of wood is 0.6. That measn

\rho_r / \rho_w = 0.6

\rho_r = 0.6\rho_w

Therefore \rho_w - \rho_r = \rho_w - 0.6\rho_w = 0.4\rho_w = 0.4*1000 = 400 kg/m^3

Let g = 9.8m/s2. We can now calculate the force that the raft can support

F = gV(\rho_w - \rho_r) = 9.8*55.135*400=216129.2N

Each person has a mass of 68kg, their weight would be

W = 68*g = 68*9.8 = 666.4N

So the maximum number of people that the raft can hold is

F / W = 216129.2 / 666.4 = 324 people

3 0
3 years ago
A 5kg rock is lifted 2m. Find the amount of work done. ​
lianna [129]

Answer:

98J

Explanation:

Given parameters:

Mass of rock  = 5kg

Height = 2m

Unknown:

Work done  = ?

Solution:

The amount of work done is given as:

 Work done  = Force x distance

 Work done = Weight x height

  Work done  = mgH

Now insert the parameters and solve;

 Work done  = 5 x 9.8 x 2 = 98J

5 0
2 years ago
Blow up a balloon and rub it against your shirt a number of times. In doing so you give the balloon a net electric charge. Now t
tamaranim1 [39]
<span>Balloons are blown up, and then rubbed against your shirt many times. The balloon then touches the ceiling. When released, the balloon remains stuck to the ceiling. The balloon is charged by contact. The ceiling has a neutral charge. The charged balloon induces a slight surface charge on the ceiling opposite to the charge on the balloon. Balloon and ceiling electric charges are opposite in sign, so they will attract each other. Since both the balloon and the ceiling are insulators, charge can not flow from one to the other. The charge on the balloon is fixed on the balloon and the charge on the ceiling remains fixed to the ceiling. It just so happens that the<span> electrostatic force the ceiling exerts on the balloon is sufficient to hold the balloon in place (i.e. overcomes gravity, etc.).</span></span>
8 0
3 years ago
5 What is the maximum speed at which a car round a curve of 25m radius on a level road if the coefficient of static friction bet
pshichka [43]

Hi there!

On a level road:

∑F = Ff (Force due to friction)

The net force is the centripetal force, so:

mv²/r = Ff

Rewrite the force due to friction:

mv²/r = μmg

Cancel out the mass:

v²/r = μg

Solve for v:

v = √rμg

v = √(25)(9.81)(0.8) = 14.01 m/s

8 0
2 years ago
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