Answer:
d = 1.19 m
Explanation:
Given that,
The force applied by the ball, F = 39.6 N
The work done on the catchers glove is 47.5 J
We need to find the distance traveled by the ball. We know that,
Work done, W = Fd
Where
d is the distance traveled

So, it will cover 1.19 m.
Answer: 0.17hp
Explanation:
Power output = power input × 85%
Power output = power input × 0.85
Power input = IV/0.85
Power input = 9×12/0.85
Power input = 108/0.85
= 127.058 watts
Converting to horse power = 127.058W × 1horse power/745.7W
= 127.058 × 0.001341
= 0.17hp
Answer:
D. location
Explanation:
The gravitational field strength of Earth is determined by the virtue of the location within the Earth's gravitational field.
That's why all objects regardless of their mass, shape, and size free fall towards the Earth with an acceleration equal to the acceleration at that location in the absence of air resistance.
According to the gravitational force between two bodies, the force experienced by one body due to the other is independent of its own mass.
The gravitational force is given by equation
F = GMm/r²
If F is the force acting on the smaller body of mass 'm', then
F = ma
Therefore, the equation becomes,
ma = GMm/r²
a = GM/r²
The value of 'a' changes with respect to the value of 'r' such that if 'r' is the radius of the Earth, then the acceleration at a height 'h' from Earth surface is given by
a = GM/(r+h)²
Here it is clear that the acceleration at any point is only the inherent property of the Earth itself.
The gravitational field strength of Earth is determined by the virtue of the location within the Earth's gravitational field.
Answer:
The dependent variable is the variable that is studied while the independent variable is the variable that is being manipulated
Answer:
4.53 second, 195 ft/s
Explanation:
u = 50 ft/s
h = 555 ft
g = 32 ft/s^2
Let the time taken by the ball to reach the ground is t and the velocity of the ball as it hits the ground is v.
Use third equation of motion


v = 195 ft /s
Thus, the ball strikes the ground with velocity 195 ft/s.
Use first equation of motion
v = u + at
195 = 50 + 32 t
32 t = 145
t = 4.53 second
Thus, the ball reach the ground in 4.53 second.