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aleksandr82 [10.1K]
3 years ago
6

Science is the process of asking scientific questions about which of the following?

Physics
2 answers:
Eva8 [605]3 years ago
4 0

the answer to your question would be D.

Gwar [14]3 years ago
3 0

Answer:

(B) The world around you.

Explanation:

Science is an endeavor that does just that: asks questions about the world around us, and attempts to answer them, too. The questions it asks, when formulated precisely, are referred to as <em>hypotheses</em> (so the answer D is incorrect here). Scientists develop theories and observe natural laws (covered by choice C), design experiments and evaluate test results (choice A). But in the end, it is all about asking scientific questions about the world around you. The choice (B) is the best answer.

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Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds
Anvisha [2.4K]
Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.

(33 \frac{m}{s}  - 11 \frac{m}{s} ) \div 10seconds \\  = 2 \frac{m}{ {s}^{2} }
That is the answer.
8 0
3 years ago
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Draw velocity-ime graph for uniform moion of an object , when initially body is at rest.
Klio2033 [76]
When the body is at rest, its speed is zero, and the graph lies on the x-axis.

When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.

It's impossible to tell, based on the given information, how these two parts of the
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8 0
3 years ago
The wavelength of the light is 0.63 micrometers. How much of this length stays in 1 centimeter
bazaltina [42]
11,066,669.
hope it help.
7 0
2 years ago
How to tackle questions on resultant force​
Solnce55 [7]

Answer:

February. we will be in the future types, I

Explanation:

Collins the best year fixed come in handy when but it at a very nice relaxing. it will not have the option?

3 0
3 years ago
The origin of an x axis is placed at the center of a nonconducting solid sphere of radius R that carries a charge +qsphere distr
MA_775_DIABLO [31]

Answer:

q=49Q/64

and

x =16R/15

Explanation:

See  attached figure.

E_{Q}= E due to sphere

E_{q}= E due to particule

E_{total}=E_{Q}-E_{q}=0  (1)

according to the law of gauss and superposition Law:

E_{Q}=E_{1}+E_{2}=E_{2} ; electric field due to the small sphere with r1=R/4

E_{Q}=kq_{2}/(r_{1}^{2})=

q_{2}=density*4/3*pi*r_{1}^{3}=Q/(4/3*pi*R^{3})*4/3*pi*r_{1}^{3}=Q*r_{1}^{3}/R^{3}

then: E_{Q}=kq_{2}/(r_{1}^{2})=k*Q*r_{1}^{3}/(R^{3}*r_{1}^{2}) = kQ/(4*R^{2})  (2)

on the other hand, for the particule:

E_{q}=kq/(r_{p}^{2})

r_{p}=2R-R/4=7R/4   ⇒    E_{q}=16kq/(49R^{2})   (3)

We replace (2) y (3) in (1):

E_{total}=E_{Q}-E_{q}=0=kQ/(4*R^{2}) - 49kq/(16R^{2})

q=49Q/64

--------------------

if R<x<2R   AND E_{total}=E_{Q}-E_{q}=0

E_{total}=E_{Q}-E_{q}=0=kQ/(x^{2}) - kq/(2R-x^{2})

remember that  q=49Q/64

then:

Q(2R-x^{2})=49/64*x^{2}

solving:

x_{1} =16R/15

x_{2} =16R

but: R<x<2R  

so : x =16R/15

7 0
3 years ago
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