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3 years ago

6

Ernest rode his bike 8 1/4 hours on Saturday and 6 1/4 on sunday he rode for a total of 88 1/2 miles for both days how long does

it take him to ride a mile on his bike

1 answer:

irina [24]3 years ago

8 0

Saturday and Sunday: 8 1/4 hours + 6 1/4 hours = 33/4 + 25/4 = 58/4 = 29/2 hours = 14 1/2 hours

A total of 88 1/2 miles = 177/2 miles for both days.

If you would like to know how long does it take him to ride one mile on his bike, you can calculate this using the following steps:

88 1/2 miles ... 14 1/2 hours
1 mile ... x hours = ?

88 1/2 * x = 1 * 14 1/2
177/2 * x = 29/2 /*2
177 * x = 29 /177
x = 29/177 hours
x = 0.16 hours

Result: It takes him 0.16 hours to ride one mile on his bike.

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According to the world atlas (2010) the population of New York City was 19,750,000, the population of Los Angeles was 15,250,000

andreev551 [17]

19,750,000
15,250,000
+ 6,945,000
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41,945,000 = forty-one nine hundred forty-five thousand

the answer is B

8 0

4 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

Can somebody help me with these problems please

mario62 [17]

Answer:

11. A. $\frac{12}{13}$

12. D. $\frac{35}{12}$

Step-by-step explanation:

11: Sin is just the side opposite of the angle divided by the hypotenuse of the triangle

Opposite of A = 36

Hypotenuse of the triangle = 39

36/39 = $\frac{12}{13}$

12. Tan is the side opposite of the angle divided by the side adjacent to the angle

Opposite of C = 35

Adjacent to C = 12

35/12 = $\frac{35}{12}$

Hope this helps!

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2 years ago

PLEASE HELP! WILL GIVE BRAINLIEST!

Alex Ar [27]

The one in the middle you can tell because when x=0 that is the y intercept and the graph had a y intercept of 4 and the middle graph had 5

6 0

3 years ago

Read 2 more answers

The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 and a standard deviation of 5,00

timama [110]

Answer: the probability that a randomly selected tire will have a life of exactly 47,500 miles is 0.067

Step-by-step explanation:

Since the life expectancy of a particular brand of tire is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = life expectancy of the brand of tire in miles.

µ = mean

σ = standard deviation

From the information given,

µ = 40000 miles

σ = 5000 miles

The probability that a randomly selected tire will have a life of exactly 47,500 miles

P(x = 47500)

For x = 47500,

z = (40000 - 47500)/5000 = - 1.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.067

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3 years ago