Ask question

Ask question

All categories

3 years ago

15

When the ancient Greeks looked at the night sky they noticed that some points of light seem to "wander" in the sky. Which term d

o we use for these wanderers today? A. stars B. nebulae C. planets D. moons

1 answer:

Ann [662]3 years ago

4 0

I think the answer might be C. Planets. Not exactly sure though... Let me know if this was correct!! :-)

You might be interested in

Solnce55 [7]

Answer:

oxygen

Explanation:

3 0

2 years ago

Calculate the molarity of 0.850 mol of Na2S in 1.70 L of solution.

Basile [38]

Molarity is simply the ratio of the number of moles of a substance over the total volume of the solution. Assuming that the addition of 0.850 moles does not change the overall volume of 1.70 L, therefore molarity is simply:

Molarity = 0.850 moles / 1.70 L = 0.5 moles / L = 0.5 M

5 0

3 years ago

Explain how Earth is heated through radiation.

sergiy2304 [10]

With this temperature the Earth Radiation will be centered on a Wavelength!

8 0

3 years ago

Which formula can be used to find velocity if kinetic energy and mass are known?

astraxan [27]

Answer:

$v = \sqrt{ \frac{2ke}{m} }$

option D is the correct option.

Here,

If an object of mass 'm' moving with a velocity'v' then,

$kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {v}^{2} = \frac{2ke}{m} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {v}^{2} = \sqrt{ \frac{2ke}{m} }$

hope this helps...

Good luck on your assignment..

5 0

3 years ago

Object A specific heat is 2.45 J/g C and object B specific heat is 0.82 J/g C. Which object will heat up more if they have the s

Artist 52 [7]

Answer: Object B will heat up more.

Explanation:

The formula for specific heat is as follows.

Q = $m C \Delta T$

Where,

Q = heat provided

m = mass

C = specific heat

$\Delta T$ = change in temperature

Now, both the objects have same mass and equal amount of heat is applied.

According to the formula, the equation will be as follows.

$Q_{1}$ = $Q_{2}$

$m C_{1}\Delta T$ = $m C_{2}\Delta T_{2}$

Cancel m from both sides, as mass is same. Therefore,

$C_{1} (T_{f} - T_{i})_A$ = $C_{2}(T_{f} - T_{i})_B$

Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.

$2.45 (T_{f})_A$ = $0.82(T_{f})_B$

Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.

Hence, object B will heat up more.

4 0

3 years ago