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3 years ago

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When the ancient Greeks looked at the night sky they noticed that some points of light seem to "wander" in the sky. Which term d

o we use for these wanderers today? A. stars B. nebulae C. planets D. moons

1 answer:

Ann [662]3 years ago

4 0

I think the answer might be C. Planets. Not exactly sure though... Let me know if this was correct!! :-)

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If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m

Nadusha1986 [10]

Answer:

$128~ATP$

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

$Number~of~Rounds=\frac{n}{2}-1$

Where "n" is the <u>number of carbons</u>, in this case "18", so:

$Number~of~Rounds=\frac{18}{2}-1~=~8$

We also have to calculate the amount of Acetyl-Coa produced:

$Number~of~Acetyl-Coa=\frac{18}{2}~=~9$

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1 $FADH_2$ and 1 $NADH$ </u>. So, if we have 8 rounds we will have 8 $FADH_2$ and 8 $NADH$ .

Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:

-) $1~FADH_2~=~2~ATP$

-) $1~NADH~=~3~ATP$

-) $Acetyl~CoA~=~10~ATP$

Now we can do the total calculation:

$(8*2)~+~(8*3)~+~(9*10)=130~ATP$

We have to <u>subtract</u> "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

$130-2=128~ATP$

In total, we will have 128 ATP.

I hope it helps!

6 0

3 years ago

Which one is the answer... a, b, or c?

jenyasd209 [6]

The answer for this one is a

8 0

3 years ago

Suppose a student titrates a 10.00-ml aliquot of saturated ca(oh)2 solution to the equivalence point with 16.08 ml of 0.0199 m h

Alborosie

Following chemical reaction is involved upon titration of Ca(OH)2 with HCl,
Ca(OH)2 + 2HCl ↔ CaCL2 + 2H2O

Above is an example of acid-base titration to generate salt and water. Here, H+ ions of acid (HCl) combines with OH- (ions) of base [Ca(OH)2] to generated H2O

Given,
concentration of HCl = 0.0199 M
Total volume of HCl consumed during titration = 16.08 mL = 16.08 X 10^(-3) L

∴, number of moles of H+ consumed = Molarity X Vol. of HCl (in L)
= 0.0199 X 16.08 X 10^(-3)
= 3.1999 X 10^-4 mol
Thus, total number of moles of [OH-] ions present initial = 3.1999 X 10-4 mol
So, initial conc. [OH-] ion = $\frac{number of moles of [OH-]}{volume of solution (L)}$ = $\frac{3.1999 X 10^(^-^4^)}{10 X 10^(^-^3^)}$ = 0.03199 M

6 0

3 years ago

What is the molar mass of cholesterol if 0.00105 mol weighs 0.406 g?

goblinko [34]

<h3>Answer: 386.67 g/mol </h3>

Explanation:

Molar Mass = Mass ÷ Mole

= 0.406 g ÷ 0.00105 mol

= 386.67 g/mol

∴ molar mass of cholesterol = 386.67 g/mol

5 0

3 years ago

Complete these metric conversions: 53 m - mm*

EleoNora [17]

Answer:

53 meters = 53000 millimeters

Explanation:

In this question we have to convert meters into millimeters .

By metric conversion,

Since, 1 meter = 1000 mm

Therefore, 53 meters = 53 × 1000

= 53000 millimeters

53 meters = 53000 millimeters is the answer.

3 0

3 years ago