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Pachacha [2.7K]
3 years ago
5

A sun-sized star will spend most of its lifetime as a:

Physics
2 answers:
nekit [7.7K]3 years ago
6 0
A sun-sized star will spend most of its lifetime as a main sequence star. It is the stage in a star's life cycle where it maintains as a stable nuclear reaction. The sun in our solar system is a clear example of this. The number of years that these stars would spend at this stage depends largely on the mass of the star. These stars would fuse atoms of hydrogen forming them into helium atoms inside their cores. Fusion reactions are continually happening as days and years pass at this stage. Approximately ninety percent of the stars found in the universe are main sequence stars.
s2008m [1.1K]3 years ago
6 0

Basically, a sun-sized star will spend most of its lifetime as main sequence star

Notably, a main sequence star is fairly average in size, and tends to spend close to 10 billion years at this stage, where its main function is continuously fusing hydrogen to helium which generates light and heat on earth, which are essential for every human and all other living organisms.

<h2>Further Explanation</h2>

At this stage, a sun-sized star maintains a steady nuclear reaction, and the amount of time it spends is determined by its mass.

All stars have starting phase, including the Sun, and their existence commences when a dense region of clouds or cold gas and dust called nebulae begins to shrink and warm up. Notably, these clouds are relatively large in size, and stars like the sun are enormous balls of plasma that unavoidably fill every space around with heat and light.

Just like humans, stars also live, and like humans, not forever. Although, a typical star could live up to several billions years are specified on the first paragraph. A star starts as a gas cloud and ends a star remnant. The life cycle of a star is in seven (7) phases. These phases are listed below:

  • The Giant gas cloud phase
  • The Protostar phase
  • The T-Tauri phase
  • The Main Sequence Star Phase
  • The expansion into red giant phase
  • The fusion into heavier elements phase
  • The supernovae and planetary nebulae phase

LEARN MORE:

  • the Sun brainly.com/question/1319415

KEYWORDS:

  • the sun
  • sun sized star
  • lifetime
  • hydrogen
  • helium
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A car is cruising at a steady speed of 35 mph. Suddenly, a cuddly puppy runs out into the road. The driver takes 1.7 seconds to
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Answer:

The distance traveled is 0.037 mi

Explanation:

The equation for the position and velocity of an accelerated object is:

x = x0 + v0 * t + 1/2 * a * t²

v = v0 + a * t

where

x = position at time t

x0 = initial position

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x = x0 + v * t where "v" is the velocity

First, let´s find the distance traveled until the driver push the brake:

The speed is constant. Then:

x = x0 + v * t (considering the origin of the reference system to be located at the point at which the driver sees the puppy, x0 = 0)

x = 35 mi/h (1 h / 3600 s) * 1.7 s = 0.017 mi

Then, the drivers moves with constant acceleration until the car stops (v = 0)

From the equation for velocity:

v = v0 + a * t

Since v = 0, we can obtain the acceleration of the car until it stops. With that acceleration, we can calculate how much distance the car moves before it stops.

0 = v0 + a * t

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a = -2.4 x 10⁻³ mi/s²

The distance traveled will be:

x = x0 + v0 * t + 1/2 * a * t²

Now x0 will be the distance traveled before the driver slows down.

x = 0.017 mi + 35 mi/h (1 h / 3600s) * 4 s + 1/2 * ( -2.4 x 10⁻³ mi/s²) * (4s)²

x = 0.037 mi

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