Answer:The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).
The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.
Explanation:
When traveling through a smoke-filled area, a person must be able to have distance of at least 4 feet in order to safely reach a fire exit. That is option C.
<h3>What is a smoke-filled area?</h3>
Smoke-filled area is an enclosed area that is filled with smoke gas that is usually made up of carbon monoxide.
The smoke-filled area is usually caused by
- Burning of plastics or chemical products
When there is smoke-filled area die to fire out break, there are some guidelines to follow to safely reach the fire exit early enough.
The importance of these guidelines include the following:
- enable rescuers to navigate a scene more quickly,
- identify risks and hazards,
- determine the safest way in and out of a building, and
- map out evacuation routes.
The affected individual should get down and crawl while taking short breath through the nose because cleaner air is nearest to the floor.
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Answer:
See explanation
Explanation:
We can convert cyclohexanol to cyclohexene in the presence of a strong acid such as sulfuric acid catalyst in a test tube at 60 oC by heating up the mixture to about 80 oC. This is a dehydration reaction so water is removed to yield the alkene. A drying agent is used to remove any trace amount of water left in the system. This overall reaction is endothermic.
Also, the reverse is the case when we want to carry out the hydration of cyclohexene to yield cyclohexanol. The overall reaction is exothermic and involves the addition of more water to the alkene and then cooling down the system to about 40 oC.
Answer:
A. 0.038 g.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
<u><em>The integration law of a first order reaction is:</em></u>
<em>kt = ln [Ao]/[A]</em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = 17,190 years.
[Ao] is the initial concentration of carbon-14 = 0.300 g.
[A] is the remaining concentration of carbon-14 = ??? g.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(17,190 years) = ln (0.300 g)/[A]
2.08 = ln (0.300 g)/[A]
Taking exponential for both sides:
8.0 = (0.300 g)/[A]
<em>∴ [A] = 0.0375 g ≅ 0.038 g</em>
